You have to distribute the 7 so the final answer will be -49-42x
The equation y= 2
has one real root and that is x=-1.
What is real roots of the equation?
We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation
-7x+12=0 is solved, the actual roots are 3 and 4.
Here given,
=> y = 2
Take y=0 then,
=> 2
=0
=>
=0
=>(x+1)=0
=> x=-1
Hence the given equation has one real root and that is x=-1.
To learn more about real roots refer the below link
brainly.com/question/24147137
#SPJ1
Answer:
Fixed expenses = 1767.07
Step-by-step explanation:
Andre calculated his variable and total expenses for last month.
His variable expenses is $2,863.09
His total expenses is $4,630.16
Now, Total expenses = Variable expenses + Fixed expenses
So, Fixed expenses = Total expenses - Variable expenses
⇒ F = T - V
⇒ F = 4630.16 - 2863.09
⇒ F = 1767.07
So, this the equation to represent Andre's fixed income. (Answer)
Answer:
1. B. point B.
2. C. point C.
3. C. point C.
Step-by-step explanation:
1. In order to find the graph's y-intercept, we need to locate the point where the line crosses the y-axis. This will always happen at x=0, therefore, the y-intercept is located at point B (0,-4)
2. In order to find the x-intercept, we need to find the point where the line crosses the x-axis. This will generally happen when y=0, so that will be point C (2,0)
3. In order to find the graph's zero, we need to find the point where y=0. In other words, the graph's zero is the point where the function is equal to zero (the x-intercept) so this will br point C again (2,0)