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andrew-mc [135]
3 years ago
14

Kerry is collecting money for school. Her goal is to get $200. She has collected $15 each from 12 people so far. How much more m

oney does she need to reacch her goal?
Mathematics
1 answer:
8090 [49]3 years ago
5 0

Answer:

20 dollars

Step-by-step explanation:

15 dollars times 12 people to see how much money she got/has right now is 180 dollars

then take 200-180 to get <u>20</u>

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Please help me answer this
balandron [24]

<em><u>Answer:</u></em>

option A is the correct answer

3 0
2 years ago
URGENT NEED IMMEDIATE SUPPORT WILLING TO GIVE BRAINLY
frozen [14]

4 hours for 18

7 hours for 25.50

Difference in hours: 7-4 = 3

Difference in cost: 25.50 - 18 = 7.50

7.50 / 3 = 2.50

A. They charge 2.50 per hour.

B. 2.50 x 4 = 10

18 - 10 = 8

The flat fee is 8 dollars

C. 8 + (2 x 2.50) = 13 dollars

8 0
3 years ago
Sylvie finds the solution to the system of equations by graphing. y = x + 1 and y = x – 1 Which graph shows the solution to Sylv
Alexeev081 [22]
The only solution is when y=y

x+1=x-1  subtract x from both sides

1=-1

This is never true so there are no solutions.  In this case it is due to the fact that both lines have the same slope and different y-intercepts.  This means that they are parallel lines that have a constant distance between them.
5 0
4 years ago
What are the characteristics of the graph of the inequality x2-2?
lara [203]

Answer:

0

Step-by-step explanation:

×2-2 = ×2 =4 =4-2=2 as in my thoughts it is kinda appropriate

8 0
3 years ago
Please help with these partial fractions!!!
VARVARA [1.3K]

a. Factorize the denominator:

\dfrac{x+14}{x^2-2x-8}=\dfrac{x+14}{(x-4)(x+2)}

Then we're looking for a,b such that

\dfrac{x+14}{x^2-2x-8}=\dfrac a{x-4}+\dfrac b{x+2}

\implies x+14=a(x+2)+b(x-4)

If x=4, then 18=6a\implies a=3; if x=-2, then 12=-6b\implies b=-2. So we have

\dfrac{x+14}{x^2-2x-8}=\dfrac3{x-4}-\dfrac2{x+2}

as required.

b. Same setup as in (a):

\dfrac{-3x^2+5x+6}{x^3+x^2}=\dfrac{-3x^2+5x+6}{x^2(x+1)}

We want to find a,b,c such that

\dfrac{-3x^2+5x+6}{x^2(x+1)}=\dfrac ax+\dfrac b{x^2}+\dfrac c{x+1}

Quick aside: for the second term, since the denominator has degree 2, we should be looking for another constant b' such that the numerator of the second term is b'x+b. We always want the polynomial in the numerator to have degree 1 less than the degree of the denominator. But we would end up determining b'=0 anyway.

\implies-3x^2+5x+6=ax(x+1)+b(x+1)+cx^2

If x=0, then b=6; if x=-1, then c=-2. Expanding everything on the right then gives

-3x^2+5x+6=ax^2+ax+bx+b+cx^2=(a-2)x^2+(a+6)x+6

which tells us a-2=-3 and a+6=5; in both cases, we get a=-1. Then

\dfrac{-3x^2+5x+6}{x^2(x+1)}=-\dfrac1x+\dfrac6{x^2}-\dfrac2{x+1}

as required.

5 0
4 years ago
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