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ryzh [129]
3 years ago
13

See the ​attached file.

Mathematics
1 answer:
Masja [62]3 years ago
3 0

f(x) = 4x - x^2

1)

f(4) = 4(4) - 4^2 = 16 - 16 = 0

f(-4) = 4(-4) - (-4)^2 = -16 - 16 = -32

f(4) - f(-4) = 0 - (-32) = 32

2)

f(3/2) = 4(3/2) - (3/2)^2

f(3/2) = 6 - 9/4 = 15/4

√f(3/2) = √(15/4) = √15 / 2

3)

f(x + h) = 4(x + h) - (x + h)^2

= 4x + 4h -(x^2 + 2xh + h^2)

= 4x + 4h -x^2 - 2xh - h^2

f(x - h) = 4(x - h) - (x - h)^2

= 4x - 4h -(x^2 - 2xh + h^2)

= 4x - 4h -x^2 + 2xh - h^2

So

[f(x + h) -f(x - h) ] / 2h

= [4x + 4h -x^2 - 2xh - h^2 - ( 4x - 4h -x^2 + 2xh - h^2 )] / 2h

=( 4x + 4h -x^2 - 2xh - h^2 - 4x + 4h + x^2 - 2xh + h^2 ) / 2h

= (8h - 4xh) / 2h

= 2h(4 -2x) / 2h

= 4 - 2x

Answer: [f(x + h) -f(x - h) ] / 2h = 4 - 2x

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Explain the circumstances for which the interquartile range is the preferred measure of dispersion. What is an advantage that th
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Answer:

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

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Step-by-step explanation:

Previous concepts

The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

IQR= Q_3 -Q_1

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Solution to the problem

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

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