All categories

3 years ago

What is the slope of the line shown

Mathematics

2 answers:

pantera1 [17]3 years ago

5 0

Answer:

Step-by-step explanation:

cause you go up 14 and over 6 then you divid by 2 and get 7/3

kenny6666 [7]3 years ago

5 0

The answer would end up being 7/3

You might be interested in

The figure shows triangle DEF and line segment BC, which is parallel to EF:

Korvikt [17]

Part A: Yes, Triangle DEF and DBC are the same triangle, but DBC is smaller than DEF because it is just a cut off of DEF.

Part B: I am pretty sure it is angle C.

Part C: I am pretty sure it is angle D.

6 0

2 years ago

Read 2 more answers

Question 3

puteri [66]

Answer:

18 inches = 1.5 feet

8 inches = 2/3 foot

y = 1.5 + (2/3)x

5 0

2 years ago

What is the area of this figure? ANSWER PLZ

schepotkina [342]

Answer:

for the area of the Circle we use A=πd

A=3.14x12 A=37.68

for a rectangle it is A=ab

A=12x15 A=180

37.68+180=142.32

your answer is 142.32 m 2

3 0

3 years ago

What are the coordinates of D' when quadrilateral ABCD is reflected over the y-axis?

Anna007 [38]

The answer should be...

(6,0) !

All you have to do is count 6 spots to the right of the origin.

4 0

4 years ago

Consider an unreliable communication channel that can successfully send a message with probability 1/2, or otherwise, the messag

Anon25 [30]

Answer:

6 times we need to transmit the message over this unreliable channel so that with probability 63/64.

Step-by-step explanation:

Consider the provided information.

Let x is the number of times massage received.

It is given that the probability of successfully is 1/2.

Thus p = 1/2 and q = 1/2

We want the number of times do we need to transmit the message over this unreliable channel so that with probability 63/64 the message is received at least once.

According to the binomial distribution:

$P(X=x)=\frac{n!}{r!(n-r)!}p^rq^{n-r}$

We want message is received at least once. This can be written as:

$P(X\geq 1)=1-P(x=0)$

The probability of at least once is given as 63/64 we need to find the number of times we need to send the massage.

$\frac{63}{64}=1-\frac{n!}{0!(n-0)!}\frac{1}{2}^0\frac{1}{2}^{n-0}$

$\frac{63}{64}=1-\frac{n!}{n!}\frac{1}{2}^{n}$

$\frac{63}{64}=1-\frac{1}{2}^{n}$

$\frac{1}{2}^{n}=1-\frac{63}{64}$

$\frac{1}{2}^{n}=\frac{1}{64}$

By comparing the value number we find that the value of n should be 6.

Hence, 6 times we need to transmit the message over this unreliable channel so that with probability 63/64.

7 0

3 years ago