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tekilochka [14]
3 years ago
5

Bob stands 12 feet above sea level. Jack dives 12 feet below sea level. What is the difference of the boys distance.

Mathematics
2 answers:
LiRa [457]3 years ago
4 0
Ones above sea level and ones below sea level
geniusboy [140]3 years ago
3 0

Answer:

The Answer is 24

Step-by-step explanation:

If Jack Is 12 feet above sea level and Jack is 12 feet below we just add both numbers to get the total distance between them

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The total length of the stage is 76 feet. If the trap doors are centered across the stage, what is the distance from the left si
weqwewe [10]
 subtract the 26 1/2 from 76 and then divide by 2

76-26 1/2 = 49 1/2 / 2 = 24 3/4

5 0
3 years ago
(32 - 2) ÷ 15 + 22 I don't know how to do this
Rus_ich [418]

Answer:

its 24 hope this helps

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
There are 3 consecutive even integers that sum to 24. What is the value of the greatest integer?
Hunter-Best [27]

Answer:

10

Step-by-step explanation:

x+x+2+x+4=24

3x+6 = 24

x=6

x+4=10

7 0
3 years ago
Read 2 more answers
Find the measure of each missing angle.
nadya68 [22]

Answer:

Step-by-step explanation:

Angle sum property of triangle: Sum of all the angles of a triangle is 180

Alternate interior angles: When two parallel lines are intersected by a transversal, the pair of angles on the inner side of  each of these lines but on the opposite side of the transversal are called  alternate interior angles

In ΔABC,

  ∠1 + 90 + 38 = 180    {angle sum property of triangle}

         ∠1 + 128 =  180

               ∠1     = 180 - 128

            \sf \boxed{\bf  \angle 1     = 52^ \°}

AB // CD and AC is transversal.

 \sf \boxed{\bf  \angle 3 = 38^\circ}   {Alternate interior angles are equal}

In ΔACD,

      ∠2 + ∠3 + 63 = 180 {angle sum property of triangle}

       ∠2 + 38 +63  = 180

               ∠2  + 101 =180

                         ∠2 = 180 - 101

                      \sf \boxed{\bf  \angle 2 = 79^ \°}

5 0
2 years ago
CALCULUS: For the function whose values are given in the table below, the integral from 0 to 6 of f(x)dx is approximated by a Re
ladessa [460]

The table gives values of <em>f(x)</em> at various <em>x</em> in the interval [0, 6], and you have to use them to approximate the definite integral,

∫₀⁶ <em>f(x)</em> d<em>x</em>

with a left-endpoint sum using 3 intervals of width 2. This means you have to

• split up [0, 6] into 3 subintervals of equal length, namely [0, 2], [2, 4], and [4, 6]

• take the left endpoints of these intervals and the values of <em>f(x)</em> these endpoints, so <em>x</em> ∈ {0, 2, 4} and <em>f(x)</em> ∈ {0, 0.48, 0.84}

• approximate the area under <em>f(x)</em> on [0, 6] with the sum of the areas of rectangles with dimensions 2 × <em>f(x)</em> (that is, width = 2 and height = <em>f(x)</em> for each rectangle)

So the Riemann sum is

∫₀⁶ <em>f(x)</em> d<em>x </em>≈ 2 ∑ <em>f(x)</em>

for <em>x</em> ∈ {0, 2, 4}, which is about

∫₀⁶ <em>f(x)</em> d<em>x </em>≈ 2 (0 + 0.48 + 0.84) = 2.64

making the answer A.

7 0
3 years ago
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