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k0ka [10]
3 years ago
8

Determine the answer to 3+(-5) and explain the steps using the number line

Mathematics
2 answers:
RUDIKE [14]3 years ago
4 0
Your answer is negative 2 and on a number line you start at 3 and go back 5 and you will land on -2
Galina-37 [17]3 years ago
3 0
Start at zero on number line 
<span>3 left and then 5 left gives 8 left. </span>
<span>(-3) + (-5) = (-8)</span>
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Sabeena had 15 3/4m long ribbon. She cut into two pieces such that the length of one pieces is 9 1/2m. Find the length of other
DochEvi [55]

Answer:

6 1/4

Step-by-step explanation:

Total length of the ribbon= 15 3/4 m= 63/4 m

One piece= 9 1/2 m= 19/2 m

Other piece length =X

X= 63/4-19/2

  =63/4-38/4

  =25/4

  =6 1/4

3 0
3 years ago
Read 2 more answers
A pair of shoes costs $30.99 and the sales tax is 5%. Use the formula C=p+Rp to find the total cost of the shoes , Where c is Th
sergeinik [125]
C=p+R x p
C=30.99 + .05 x 30.99
Order of operations states do the multiplication first
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7 0
4 years ago
What is the probability that two different colored marbles are drawn, given that the first marble drawn is red?.
inessss [21]

Answer:

what are the color of the marbles that are not red?

Step-by-step explanation:

5 0
2 years ago
Gravity Hospital purchased a new item of equipment on January 1,20X1. The equipment has an estimated useful life of ten years an
qaws [65]

Answer:

  $25000

Step-by-step explanation:

If the salvage value is 20% of the cost, then 80% of the cost will be depreciated over 10 years. Over the 5 years from Jan 1 20X1 to Dec 31 20X5, the $10,000 accumulated depreciation represents 5/10 of that 80%, or 40% of the initial cost.

  $10,000 = 0.40 × cost

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The acquisition cost of the equipment was $25,000.

8 0
3 years ago
Does anybody know how to do time with exponential decay
My name is Ann [436]
<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots

and so on. The pattern is such that you arrive at

b_n=0.12^{n-1}b_1

and so the amount of air remaining after 50 breaths is

b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}

which is a very small number close to zero.</span>
5 0
3 years ago
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