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NemiM [27]
3 years ago
9

The following six independent length measurements were made (in feet) for a line: 736.352, 736.363, 736.375, 736.324, 736.358, a

nd 736.383. Determine the standard deviation of the measurements.
Mathematics
1 answer:
horrorfan [7]3 years ago
6 0

Answer:

Assuming population data

\sigma = \sqrt{0.000354}=0.0188

Assuming sample data

s = \sqrt{0.000425}=0.0206

Step-by-step explanation:

For this case we have the following data given:

736.352, 736.363, 736.375, 736.324, 736.358, and 736.383.

The first step in order to calculate the standard deviation is calculate the mean.

Assuming population data

\mu = \frac{\sum_{i=1}^6 X_i}{6}

The value for the mean would be:

\mu = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359

And the population variance would be given by:

\sigma^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6}

And we got \sigma^2 =0.000354

And the deviation would be just the square root of the variance:

\sigma = \sqrt{0.000354}=0.0188

Assuming sample data

\bar X = \frac{\sum_{i=1}^6 X_i}{6}

The value for the mean would be:

\bar X = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359

And the population variance would be given by:

s^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6-1}

And we got s^2 =0.000425

And the deviation would be just the square root of the variance:

s = \sqrt{0.000425}=0.0206

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