Question

HELP PLEASEEE. I DONT UNDERSTAND

Answer 1

Answer:

D

Step-by-step explanation:

So we have the equation:

$x^2-6x+58=0$

And we want to solve for x.

We can solve it by completing the square.

First, subtract 58 from both sides:

$x^2-6x=-58$

Divide the b term by 2 and square it:

$(-6)/2=-3\\(-3)^2=9$

So, add 9 to both sides:

$(x^2-6x+9)=-58+9$

On the left, the perfect square trinomial pattern. Add on the right. So:

$(x-3)^2=-49$

Take the square root of both sides:

$x-3=\pm \sqrt{-49}$

The square root of -49 is 7i:

$x-3=\pm 7i$

Add 3 to both sides:

$x=3\pm 7i$

So, our answer is D.

And we're done!