If I did everything correctly, It should be DEF.
Hope you get an A :d
Answer:
Step-by-step explanation:
The line can be written as
Since the line is contained in the plane, if we take any two points of this line they will lie in the plane.
Give values for t =0 and 1
We get two points (x,y,z) as (1,3,0) and (3,2,1)
Now we have another non collinearpoint (1,1,1) (given)
The plane equation can be written using these 3 points using the determinant.
x-x1 y-y1 z-z1
x2-x1 y2-y2 z2-z1
x3-x1 y3-y1 z3-z1 =0
Substitute the values form the points.
We get
Expand the determinant as
(x-1)(-1+2)-(y-3)(2-0)+z(-4-0) =0
x-1-2y+6-4z =0
x-2y-4z+5 =0
Answer:
Min = 11
Q1 = 13
Median = 15
Q3 = 17
Max = 22
Step-by-step explanation:
The five-number summary that is displayed by the box plot above are:
The minimum value: the data value at the start of the whisker to your left = 11
The Q1 value: the data value at the beginning of the edge of the rectangular box = 13
The Median value: the data value at the vertical line that divides the rectangular box into two = 15
Q3 value: the data value at the end of the rectangular box = 17
Max: 22
Answer:
9
Step-by-step explanation:
45 devided by 5 = 9