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3 years ago

10

HURRY ASAP PLZZZZ ANYONE???? There are 25 towns in a certain country, and every pair of them is connected by a train route. How

many train routes are there?

2 answers:

Mila [183]3 years ago

8 0

Answer:

300

Step-by-step explanation:

25·24/2=300

Julli [10]3 years ago

4 0

Answer:

25 train routes

Step-by-step explanation:

The train routes go from 1-2, 2-3, 3-4, 4-5, ,and so on, but there is also one that goes from 25-1. If you notice, there when we get to 4-5, there are 4 train routes which means that if there are 25 towns, then there are 24 train routes, but since 25 and 1 are connected then there are 25 routes. Hope this helps!

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I need help with my math homework. The questions is: Find all solutions of the equation in the interval [0,2π).

Aleksandr-060686 [28]

Answer:

$\frac{7\pi}{24}$ and $\frac{31\pi}{24}$

Step-by-step explanation:

$\sqrt{3} \tan(x-\frac{\pi}{8})-1=0$

Let's first isolate the trig function.

Add 1 one on both sides:

$\sqrt{3} \tan(x-\frac{\pi}{8})=1$

Divide both sides by $\sqrt{3}$ :

$\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}$

Now recall $\tan(u)=\frac{\sin(u)}{\cos(u)}$ .

$\frac{1}{\sqrt{3}}=\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}$

or

$\frac{1}{\sqrt{3}}=\frac{-\frac{1}{2}}{-\frac{\sqrt{3}}{2}}$

The first ratio I have can be found using $\frac{\pi}{6}$ in the first rotation of the unit circle.

The second ratio I have can be found using $\frac{7\pi}{6}$ you can see this is on the same line as the $\frac{\pi}{6}$ so you could write $\frac{7\pi}{6}$ as $\frac{\pi}{6}+\pi$ .

So this means the following:

$\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}$

is true when $x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi$

where $n$ is integer.

Integers are the set containing {..,-3,-2,-1,0,1,2,3,...}.

So now we have a linear equation to solve:

$x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi$

Add $\frac{\pi}{8}$ on both sides:

$x=\frac{\pi}{6}+\frac{\pi}{8}+n \pi$

Find common denominator between the first two terms on the right.

That is 24.

$x=\frac{4\pi}{24}+\frac{3\pi}{24}+n \pi$

$x=\frac{7\pi}{24}+n \pi$ (So this is for all the solutions.)

Now I just notice that it said find all the solutions in the interval $[0,2\pi)$ .

So if $\sqrt{3} \tan(x-\frac{\pi}{8})-1=0$ and we let $u=x-\frac{\pi}{8}$ , then solving for $x$ gives us:

$u+\frac{\pi}{8}=x$ ( I just added $\frac{\pi}{8}$ on both sides.)

So recall $0\le x$ .

Then $0 \le u+\frac{\pi}{8}$ .

Subtract $\frac{\pi}{8}$ on both sides:

$-\frac{\pi}{8}\le u$

Simplify:

$-\frac{\pi}{8}\le u$

$-\frac{\pi}{8}\le u$

So we want to find solutions to:

$\tan(u)=\frac{1}{\sqrt{3}}$ with the condition:

$-\frac{\pi}{8}\le u$

That's just at $\frac{\pi}{6}$ and $\frac{7\pi}{6}$

So now adding $\frac{\pi}{8}$ to both gives us the solutions to:

$\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}$ in the interval:

$0\le x$ .

The solutions we are looking for are:

$\frac{\pi}{6}+\frac{\pi}{8}$ and $\frac{7\pi}{6}+\frac{\pi}{8}$

Let's simplifying:

$(\frac{1}{6}+\frac{1}{8})\pi$ and $(\frac{7}{6}+\frac{1}{8})\pi$

$\frac{7}{24}\pi$ and $\frac{31}{24}\pi$

$\frac{7\pi}{24}$ and $\frac{31\pi}{24}$

5 0

3 years ago

Help please if you still up im really struggling

Papessa [141]

Answer:

discriminant =0

1 real root

Step-by-step explanation:

The discriminant is b^2 -4ac

when the equation is written in the form ax^2 +bx+c

f(x) = 3x^2 +24x+48

a = 3 b = 24 and c =48

discriminant = 24^2 - 4(3)*(48)

=576-576

=0

If the discriminant >0 we have 2 real roots

if discriminant = 0 we have 1 real root

if discriminant <0 we have 2 complex roots

3 0

3 years ago

Here is an inequality: 7x+6/2 < 3x +2

Archy [21]

Answer:

x=1

Step-by-step explanation:

7 0

3 years ago

Are trapezoids always, sometimes, or never a parallelogram?

tatyana61 [14]

THEY ARE ALWAYS PARALLELOGRAMS

8 0

2 years ago

Read 2 more answers

Use the drawing tool(s) to form the correct answer on the provided number line. Consider the functions below. Represent the inte

Leno4ka [110]

In order to solve this problem, we will need a little more information, for example, we need to know what the functions are. Let's say the problem looks like this:

Use the drawing tool(s) to form the correct answer on the provided number line. Consider the functions below.

$f(x)=|3x|-3$

and

$g(x)=-x^{2}+8x-5$

Represent the interval where both functions are increasing on the number line provided.

Answer:

See attached picture

Step-by-step explanation:

Since this problem is posted on the algebra section of Brainly, I assume we will need to make use of an algebraic approach to solve this. Basically, the idea is to graph the functions and find the x-values for which both functions increas. In order to graph the functions, we will need to build a table with points for each of the functions. In order to graph the functions you need to pick the x-values you wish and evaluate them in the given functions. (See attached pictures)

Once you got the desired points, you can plot them in the coordinate axis and find the x-values for which both graphs will be increasing. If we take a close look at the graphs we can see the f(x) graph increases in the interval:

(0,∞)

and the g(x) graph increases in the interval:

(-∞,4)

so the interval in which both graphs are increasing will be the region where both intervals cross each other, which will be (0,4)

so that's the interval we draw on our number line. (see attached picture.

7 0

3 years ago