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PilotLPTM [1.2K]

3 years ago

8

I add 20 to my number and subtract 17 from the new number. the answer is 37. what is my number?

2 answers:

Savatey [412]3 years ago

7 0

Your new number is 54

valentinak56 [21]3 years ago

3 0

34 im pretty sure
i have to use 20 characters so i am typing this

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Given that the student is male what is the probability that he considers himself to be a "Liberal"? Round your answer to three d

Furkat [3]

If you focus on the "Male" row, you'll see that there are 48 liberals out of 124 surveyed men.

So, the probability of having a liberal, knowing that he's a male, is

$\dfrac{48}{124}=0.3870967742\approx 0.387$

3 0

3 years ago

The Apple, Inc. sales manager for the Chicago West Suburban region is disturbed about the large number of complaints her office

ankoles [38]

Answer:

0.6856

Step-by-step explanation:

$\text{The missing part of the question states that we should Note: that N(108,20) model to } \\ \\ \text{ } \text{approximate the distribution of weekly complaints).]}$

Now; assuming X = no of complaints received in a week

Required:

To find P(77 < X < 120)

Using a Gaussian Normal Distribution ( $\mu =$ 108, $\sigma$ = 20)

Using Z scores:

$Z = \dfrac{77-108}{20} \\\\ Z = -\dfrac{35}{20} \\ \\ Z -1.75$

As a result X = 77 for N(108,20) is approximately equal to to Z = -1.75 for N(0,1)

SO;

$Z = \dfrac{120-108}{20} \\ \\ Z = \dfrac{12}{20}\\ \\ Z = 0.6$

Here; X = 77 for a N(108,20) is same to Z = 0.6 for N(0,1)

Now, to determine:

P(-1.75 < Z < 0.6) = P(Z < 0.6) - P( Z < - 1.75)

From the standard normal Z-table:

P(-1.75 < Z < 0.6) = 0.7257 - 0.0401

P(-1.75 < Z < 0.6) = 0.6856

3 0

2 years ago

Factor the expression completely over the complex numbers.<br><br> x4−625

marusya05 [52]

Your factoring answer is: (x^2+25)(x+5)(x-5)

6 0

3 years ago

What are the properties of an obtuse triangle

coldgirl [10]

<span>An obtuse triangle will have one and only one obtuse angle. </span>

<span>The other two angles are acute angles.</span>

<span>The sum of the two angles other than the obtuse angle is less than 90º.<span /></span>

<span><span>The side opposite to the obtuse angle is the longest side of the triangle.</span></span>

<span><span>
</span><span>The points of concurrency, the Circumcenter and the Orthocenter lie outside of an obtuse triangle, while Centroid and Incenter lie inside the triangle.
</span></span>

5 0

3 years ago

What is the correct first step to solve this system of equations by elimination?

storchak [24]

$\bold{\huge{\pink{\underline{ Solution }}}}$

$\bold{\underline{ Given }}$

<u>We </u><u>have </u><u>given </u><u>two </u><u>linear </u><u>equations </u><u>that</u><u> </u><u>is </u><u>2x </u><u>-</u><u> </u><u>3y </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>and </u><u>x</u><u> </u><u>+</u><u> </u><u>3y </u><u>=</u><u> </u><u>1</u><u>2</u><u> </u><u>.</u>

$\bold{\underline{ To \: Find }}$

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>x </u><u>and </u><u>y </u><u>by </u><u>elimination </u><u>method</u><u>. </u>

$\bold{\underline{ Let's \: Begin }}$

$\sf{ 2x - 3y = -6 ...eq(1)}$

$\sf{ x + 3y = 12 ...eq(2)}$

<u>Multiply </u><u>eq(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>by </u><u>2</u><u> </u><u>:</u><u>-</u>

$\sf{ 2( x + 3y = 12 )}$

$\sf{ 2x + 6y = 24 }$

<u>Subtract </u><u>eq(</u><u>1</u><u>)</u><u> </u><u>from </u><u>eq(</u><u>2</u><u>)</u><u> </u><u>:</u><u>-</u>

$\sf{ 2x + 6y -( 2x - 3y) = 24 -(-6)}$

$\sf{ 2x + 6y - 2x + 3y = 24 + 6 }$

$\sf{ 9y = 30 }$

$\sf{ y = 30/9}$

$\sf{\red{ y = 10/3}}$

<u>Now</u><u>, </u><u> </u><u>Subsitute</u><u> </u><u>the </u><u>value </u><u>of </u><u>y </u><u>in </u><u>eq(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>

$\sf{ 2x - 3(10/3) = -6 }$

$\sf{ 2x - 10 = -6 }$

$\sf{ 2x = -6 + 10}$

$\sf{ x = 4/2}$

$\sf{\red{ x = 2}}$

Hence, The value of x and y is 2 and 10/3

6 0

2 years ago