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kap26 [50]
3 years ago
10

Write (2x - 5)2 as a trinomial.

Mathematics
2 answers:
solniwko [45]3 years ago
7 0

Answer:

4x^2-20x+25

Step-by-step explanation:

(2x-5)^{2} \\(2x)^2+2(2x)(-5)+(-5)^2\\4x^2-20x+25

sashaice [31]3 years ago
4 0

Answer:

4x^2-20x+25

Step-by-step explanation:

You can use the formula:

(u+v)^2=u^2+2uv+v^2.

(2x-5)^2=(2x)^2+2(2x)(-5)+(-5)^2

(2x-5)^2=4x^2-20x+25.

You could also use foil:

(2x-5)^2=(2x-5)(2x-5)

First: 2x(2x)=4x^2

Outer: 2x(-5)=-10x

Inner: -5(2x)=-10x

Last: -5(-5)=25

--------------------------Add.

4x^2-20x+25

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Step-by-step explanation:

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3 years ago
Solve for y -5y+8=-3y+10 what is the answer
masha68 [24]
-5y + 8 = -3y + 10
We need to get y on one side.
Add 3y to both sides.
-2y + 8 = 10
We need to get 2y by itself.
Subtract 8 from both sides.
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Divide both sides by -2 to solve for y.
y = -1

I hope this helps!
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The sum of two numbers is 68 . the smaller number is 12 less than the larger number. what are the numbers?
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5 0
3 years ago
Find the distance between the complex numbers. z1 = 9 - 9i z2 = 10 - 9i
steposvetlana [31]

Answer:

The distance between the two given complex numbers = 9

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<u><em>Step(i):</em></u>-

Given  Z₁ = 9 - 9 i    and Z₂ = 10 -9 i

Let A and B represent complex numbers Z₁ and Z₂ respectively on the argand plane

⇒ A =  Z₁ = x₁ +i y₁ = 9 - 9 i and

    B = Z₂ = x₂+ i y₂ = 10 -9 i

Let (x₁ , y₁) = ( 9, -9)

     (x₂, y₂) = (10, -9)

<u>Step(ii)</u>:-

<em>The distance between the two points are </em>

    A B   =   \sqrt{(x_{2} - x_{1})^{2}+(y_{2} - y_{1})^{2}    }

    A B =   \sqrt{(10 - 1)^{2}+(-9 - (-9))^{2}    }

   AB   = \sqrt{(9)^{2} +(-9+9)^{2} }

 <em> AB    =  √81 = 9</em>

<u><em>Conclusion:-</em></u>

The distance between the two given complex numbers = 9

<u><em></em></u>

3 0
3 years ago
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