Answer:
The small opening present on the epidermis which helps with exchange of gasses and transpiration is called stomata. Since most of the water (90%) is lost through stomata it regulates the level of excess water in the plant.
Explanation:
<h3>please mark me as brainliest </h3>
Answer:
B. They use energy from the sun to make their own food
you need to post the map so that people can help you
Attached is a table. I found the exercise on another page on the internet and the sample of 100 individuals was categorised on a table - easier to understand than as it is presented here.
<span>"(a) what is the probability that a random sampled individual, gene 1 is dominant" - We should first add up all of the individuals that are dominant for gene 1 (56+24) and then divide it by the total number of individuals (100).
</span>
=0.8
<span>The probability is of 8 in 10 individuals.
"</span><span>(b) what is the probability that a random sampled individual, gene 2 is dominant" - Follow the same logic as in the previous question.
</span>
=0.7
<span>The probability is of 7 in 10 individuals.
</span>"<span>(c) given that gene 1 is dominant, what is the probability that gene 2 is dominant" - Because we are considering those that are dominant for gene 1, our total number of individuals is the total individuals that are dominant for gene 1 and not the whole 100. Once we have this restriction, and we want to know the probability that gene 2 is dominant in these individuals, we should also only consider those that are dominant for gene 2.
</span>
=0.7
The probability that gene 2 is dominant, given that that gene 1 is dominant, is of 7 in 10 individuals.
Answer:
allelic frequency a = 30%
allelic frequency A = 70%
Explanation:
You are studying a population of sparrows in which the phenotype is determined by a single locus. Only two alleles for this locus are known for this population, which are distinguished by the codes 'A' and 'a'. The distribution of phenotypes in the population indicates that 49% of the population is homozygous 'AA', 42% is heterozygous and 9% 'aa' homozygous. How is the allele frequency for 'A' and 'a' determined based on these observations?
According to the case, the allelic frequency for A and a will be searched with the data:
homozygotes AA = 49%
heterozygotes Aa = 42%
homozygous aa = 9%
Frequency of homozygotes 'aa'
(q 2) = 9/100 = 0.09
we can obtain the allelic frequency of a through the following formula:
a (q) = √0.09
The result will be
= 0.3
we change to percentage
= 30%
we have the following formula
p + q = 1
to find the allele frequency A, represented by p
p = 1 - 0.3
we get the following result
p = 0.7
we change to percentage
= 70%