Answer:
bb would be the phenotype white fur
Explanation:
B is dominant over b. It takes two recessive alleles to produce the phenotype of white fur.
Answer:
FALSE
Explanation:
False
Explanation:
In the court of law, there's the plaintiff and defendant
The plaintiff brings the case or have a case against someone in the court of law
The defendant
Is the accused in the court of law
Here,
Fed is the accuser
Wilma is the accused
The bile is produced by the liver and the gallblader only serves as storage between meals. The main stimulus for the release of bile from the gallblader comes from the nervous system,after food is put in the mouth.
Answer:
Phenotype genotype Number of individuals
Red RR 245
Pink Rr 210
White rr 45
Number of alleles in total
R = 245 + 245 + 210 = 700 ---> 700/1000= 0.7 R frequency
r = 210 + 45 + 45 = 300 -----> 300/1000 = 0.3 r frequency
Predict (Hardy Weinberg) genotype frequencies=
p^2 + 2pq + q^2 = 1
p= 0.7
q=0.3
0.49 + 0.42 + 0.9 =1
According Punnett Squares in F1 we have=
Rr* rr = Rr 50% and rr 50%
Answer:
C)Parental: 41% Dr, 41% dR; recombinant: 9% DR, 9% dr.
Explanation:
The notation Dr/dR for genotypes means that one homologous chromosome has the alleles Dr and the other homologous chromosome has the alleles dR.
The heterozygous plant Dr/dR will produce 4 types of gametes: two identical to the chromosmes the individual has in its somatic cells (called parental), and two gametes which will be a mix of the alleles in the homologous chromosomes (called recombinant).
- Dr: parental
- dR: parental
- DR: recombinant
- dr: recombinant
To calculate the frequency of each type of gamete, we must use the formula:
Distance (map units) / 100 = frequency of recombination.
18 mu / 100 = 0.18.
The total frequency of recombination between the genes D and R is 0.18, but every time crossing over happens, two recombinant gametes are generated. Therefore, each recombinant gamete will have a frequency of 0.18/2=0.09 = 9%.
The frequency of parental gametes will be:
1 - frequency of recombinant gametes
1 - 0.18 = 0.82
But there are 2 parental gametes, so each of them will have a frequency of 0.82/2=0.41 = 41%.
