F(x) = x - 2sinx
To find for what values of x graph has tangents we need to differentiate function f(x).
f'(x) = 1-2cosx
Now, if we want to have horizontal tangents we need to make function f'(x) equal to 0 because at minimum or maximum of function f(x) tangent is horizontal.
1-2cosx = 0
cosx = 1/2
x = pi/3 + 2*n*pi and
x = -pi/3 + 2*n*pi
Explanation: cosx = 1/2 for both 60° and -60°. If we make one circle cosx will be equal to 1/2 for 420 and 300 degrees. Writing degrees in radians (using pi) we can write formulas above where 2*pi represents one full circle and n is an integer which represents how many circles we made.
Answer:
Use the appropriate entry method for piecewise functions for the graphing calculator of interest.
Step-by-step explanation:
For Desmos, the entry looks like ...
f(x) = {x ≤ 2: -2x-1,-x+4}
_____
For a TI-84 calculator, the entry may look like ...
Y₁ = (-2X–1)(X≤2) + (-X+4)(X>2)
The symbols ≤ and > come from the TEST menu, which is the (2nd) shift of the MATH key.
Note that the function is the sum of the pieces, each piece multiplied by a test. For something like 0≤x<2, the multiplier would be a pair of tests:
... (0≤X)(X<2)
Step-by-step explanation:
x = -12
y = x/2 + 9
y = -12/2 + 9
y = -6 + 9
y = 3
Answer:
An obtuse triangle has 1 obtuse angle and 2 acute angles.
Answer:
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