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Alinara [238K]
3 years ago
9

Please find the vertex

Mathematics
1 answer:
luda_lava [24]3 years ago
8 0
<h3>Answer: Vertex is (2,2)</h3>

=====================================

Explanation:

The equation

y = -3x^2 + 12x - 10

is in the form

y = ax^2 + bx + c

with a = -3, b = 12, c = -10

Plug the 'a' and 'b' values into the equation below to find the x coordinate of the vertex

h = -b/(2a)

h = -12/(2*(-3))

h = -12/(-6)

h = 2

The x coordinate of the vertex is h = 2, which is then used to find the y coordinate of the vertex

y = -3x^2 + 12x - 10

y = -3(2)^2 + 12(2) - 10

y = -3(4) + 12(2) - 10

y = -12 + 24 - 10

y = 12 - 10

y = 2

The y coordinate of the vertex is k = 2

The vertex is (h,k) = (2,2)

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Solve for x! , Please answer!!
tatuchka [14]

Answer:

Value of x = -7

Step-by-step explanation:

Given:

First angle = 83°

Second angle = 24°

Third angle = (38 - 5x)°

Find:

Value of x

Computation:

We know that sum of all interior angle in triangle is 180°

So,

83 + 24 + 38 - 5x = 180

145 - 5x = 180

-5x = 35

x =  -7

Value of x = -7

7 0
3 years ago
Tim can complete 168 math problems in six minutes. How many problems could he complete in one minute?
Zolol [24]
168/6 = 28

Tim can solve 28 problems in one minute.
5 0
4 years ago
What are the measurements of a c and b​
finlep [7]

Answer:

a=90

c=40

b=70

Step-by-step explanation:

a is right angle so 90

c is 160-90-30=40

b is 150-80=70

7 0
3 years ago
Read 2 more answers
Deondra has 57 m of fencing to build a three-sided fence around a rectangular plot of
Law Incorporation [45]

(L=17m and W=20m) and (L=40m and W=8.5m) are the possible dimensions (length and width) of the field given that the three sided fence has a length of 57m the area of the land is 340 square meters. This can be obtained by forming quadratic equation for the data.

 

<h3>Calculate the set of possible dimensions (length and width) of the field:</h3>

Let length be L and width be W.

Given that,

three sided fence has a length of 57m,

⇒ 2W + L = 57 m ⇒ L = 57 - 2W

the area of the land is 340 square meters

length × width = 340 ⇒ L × W = 340

(57 - 2W)W = 340

57W - 2W² = 340

2W² - 57W + 340 = 0

Solve for W using quadratic formula,

a = 2, b = -57, c = 340

W = (-b±√b²-4ac)/2a  

   = (57±√3249-2720)/4

   = (57±√529)/4

   = (57±23)/4

W = 20 m and W = 8.5 m  

For W=20, L=57-2(20) = 17

For W=8.5, L=57-2(8.5) = 40

Hence (L=17m and W=20m) and (L=40m and W=8.5m) are the possible dimensions (length and width) of the field given that the three sided fence has a length of 57m the area of the land is 340 square meters.

Learn more about quadratic equations:

brainly.com/question/5975436

#SPJ1

4 0
2 years ago
I serious help. a ton​
kap26 [50]

Answer:

Since BD bisects Angle ABC, Angle ABD = Angle DBC

3x+6=7x-18

Subtract 6 from both sides:

3x+6-6=7x-18-6

3x=7x-24

Subtract 7x from both sides:

3x-7x=7x-24-7x

-4x=-24

Divide both sides by -4:

\frac{-4x}{-4}=\frac{-24}{-4}

x=6

Angle ABD=3x+6=3(6)+6=18+6=24

Angle CBD=7x-18=7(6)-18=42-18=24

Angle ABC=ABD+CBD=24+24=48

8 0
3 years ago
Read 2 more answers
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