Question

In a titration experiment, a 10.00 ml sample of H2SO4 was titrated with 33.25 mL of 0.777 M KOH.

Answer 1

Answer:

1.292 M

Explanation:

In order to calculate the concentration of H2SO4, we need to get the balanced equation of reaction first;

$H_2SO_4 + 2KOH --> K_2SO_4 + 2H_2O$

Using the formula:

CaVa/CbVb = na/nb

where Ca = concentration of acid, Va = volume of acid, Cb = concentration of base, Vb = volume of base, na = number of moles of acid, and nb = number of moles of base.

In this case, Ca =?, Va = 10.00 ml, Cb = 0.777, Vb = 33.25 ml, na = 1, nb = 2

Ca = CbVbna/Vanb = 0.777 x 33.25 x 1/10 x 2

Ca = 1.292 M

Hence, the concentration of H2SO4 is 1.292 M