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iris [78.8K]
3 years ago
10

Round 375.52 to the nearest one

Mathematics
2 answers:
Anestetic [448]3 years ago
6 0
I’m just here to get points
Oksana_A [137]3 years ago
5 0

376. I hope I helped!

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The diagram shows a sector of a circle of radius 4 cm.<br> work out the length of the arc abc
Zielflug [23.3K]
Need to know the angle for this I think?
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3 years ago
What are the solutions to this equation?<br><br> 16x2 + 9 = 25
mash [69]

Answer:

Step-by-step explanation:

Solution

= −1

= 1

3 0
3 years ago
Read 2 more answers
. Consumer Awareness In 1986, the average cost of a new midsize four-door sedan was $9000. In 1991, the average cost was $12,000
eduard

<u>Answer-</u>

\boxed{\boxed{y=9000(1.0592)^x}}

<em>And cost of a car in the year 2000 will be </em><em>$20134.18</em>

<u>Solution-</u>

Let's assume,

x = number of years after 1986

y = average cost of sedan in dollar

The exponential model that will model the scenario will be in the form of,

y=ab^x

where a and b are constants

As given that, in 1986 average cost of sedan was $9000 and in 1991 average cost of sedan was $12000

So, the points (0, 9000) and (5, 12000) will satisfy or lie on the exponential curve.

Putting (0, 9000) in the equation,

\Rightarrow 9000=ab^0

\Rightarrow a\times 1=9000

\Rightarrow a=9000

Now, the equation becomes y=9000b^x

Putting (5, 12000) in this equation,

\Rightarrow 12000=9000b^5

\Rightarrow b^5=\dfrac{12000}{9000}

\Rightarrow b=\sqrt[5]{\dfrac{4}{3}}

\Rightarrow b=1.0592

Putting the values,

y=9000(1.0592)^x

As we have to calculate the cost of sedan in 2000, so putting x=14(as 2000-1986=14),

y=9000(1.0592)^{14}=20134.18

Therefore, cost of a car in the year 2000 will be $20134.18

8 0
3 years ago
If f(x) = 4<br>how much is f(6*x)? <br><br>​
Bingel [31]

Answer:

24

Step-by-step explanation:

x=4

f(6*x) becomes f(6*4)

f(6*4)=24

5 0
3 years ago
Find the domain and the range of the relation. Determine whether the relation is a function.
luda_lava [24]

Answer:

Domain = -3, 2, -8

Range = 1, 6, -6

Function? No

Step-by-step explanation:

Domain = x-values(no repeats)

Domain = -3, 2, -8

Range = y-values(no repeats)

Range = 1, 6, -6

Function?

No, the domain is repeating. Range can repeat but domain cannot

For more info about deciding if its a function or not, learn about the VLT

(vertical line test)

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

6 0
3 years ago
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