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3 years ago

Consider the following graph of a linear function.

Mathematics

1 answer:

HACTEHA [7]3 years ago

3 0

Answer:

I don't see a picture, did you add one? ill wait for your response

Step-by-step explanation:

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Solve for x to the nearest tenth...please help me lol

sleet_krkn [62]

Answer:

Step-by-step explanation:

A^2+B^2=C^2 is the pythagorean theorem to find a missing siede of a triangle.

First triangle on the right:

5^2+B^2=10^2

25+B^2=100

B^2=75

B=8.66025404

B=8.7

Second triangle of left:

3^2+B^2=8.7^2

9+B^2=75.69

B^2=66.69

B= 8.16639455

B=8.2

x=8.2

3 0

2 years ago

What is an equation of the line that passes through the points (-2,-5) and (-1,1)

alekssr [168]

Answer:

Slope = 6

Step-by-step explanation:

Slope = $\frac{y^{2}-y^{1} }{x^{2}-x^{1} } =\frac{1-(-5)}{-1-(-2)}=\frac{1+5}{-1+2}=\frac{6}{1}=6$

6 0

2 years ago

Which of the following is an infinite series?

max2010maxim [7]

Answer:

for the first question it would be A. 4+8+16+32 because infinite series are such as :

9,18,36,72,144,288

10,20,40,80,160,

so basically its multiplying *2

I cant do #2 without seeing the formula

4 0

2 years ago

I NEED HELP PLEASE !!!Sketch a rectangular prism that has a volume of 36 cubic cm. Label the dimensions of each side on the pris

navik [9.2K]

Answer:

Height: 3cm
Length: 6cm
Width: 2cm

Step-by-step explanation:

To sketch such a Rectangular Prism, all you need to do is to ensure that the product of the dimensions gives 36 cubic cm.

An example is attached:

Height: 3cm
Length: 6cm
Width: 2cm

Volume of a rectangular prism = Length X Height X Width

=6 X 3 X 2

Volume=36 cubic cm

8 0

3 years ago

Evaluate the interval (Calculus 2)

Darya [45]

Answer:

$2 \tan (6x)+2 \sec (6x)+\text{C}$

Step-by-step explanation:

<u>Fundamental Theorem of Calculus</u>

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

$\displaystyle \int \dfrac{12}{1-\sin (6x)}\:\:\text{d}x$

$\boxed{\begin{minipage}{5 cm}\underline{Terms multiplied by constants}\\\\$\displaystyle \int a\:\text{f}(x)\:\text{d}x=a \int \text{f}(x) \:\text{d}x$\end{minipage}}$

If the terms are multiplied by constants, take them outside the integral:

$\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)}\:\:\text{d}x$

Multiply by the conjugate of 1 - sin(6x) :

$\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)} \cdot \dfrac{1+\sin(6x)}{1+\sin(6x)}\:\:\text{d}x$

$\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{1-\sin^2(6x)} \:\:\text{d}x$

$\textsf{Use the identity} \quad \sin^2 x+ \cos^2 x=1:$

$\implies \sin^2 (6x) + \cos^2 (6x)=1$

$\implies \cos^2 (6x)=1- \sin^2 (6x)$

$\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{\cos^2(6x)} \:\:\text{d}x$

Expand:

$\implies 12\displaystyle \int \dfrac{1}{\cos^2(6x)}+\dfrac{\sin(6x)}{\cos^2(6x)} \:\:\text{d}x$

$\textsf{Use the identities }\:\: \sec \theta=\dfrac{1}{\cos \theta} \textsf{ and } \tan\theta=\dfrac{\sin \theta}{\cos \theta}:$

$\implies 12\displaystyle \int \sec^2(6x)+\dfrac{\tan(6x)}{\cos(6x)} \:\:\text{d}x$

$\implies 12\displaystyle \int \sec^2(6x)+\tan(6x)\sec(6x) \:\:\text{d}x$

$\boxed{\begin{minipage}{5 cm}\underline{Integrating $\sec^2 kx$}\\\\$\displaystyle \int \sec^2 kx\:\text{d}x=\dfrac{1}{k} \tan kx\:\:(+\text{C})$\end{minipage}}$

$\boxed{\begin{minipage}{6 cm}\underline{Integrating $ \sec kx \tan kx$}\\\\$\displaystyle \int \sec kx \tan kx\:\text{d}x= \dfrac{1}{k}\sec kx\:\:(+\text{C})$\end{minipage}}$

$\implies 12 \left[\dfrac{1}{6} \tan (6x)+\dfrac{1}{6} \sec (6x) \right]+\text{C}$

Simplify:

$\implies \dfrac{12}{6} \tan (6x)+\dfrac{12}{6} \sec (6x)+\text{C}$

$\implies 2 \tan (6x)+2 \sec (6x)+\text{C}$

Learn more about indefinite integration here:

brainly.com/question/27805589

brainly.com/question/28155016

3 0

2 years ago