Answer:
between 30 yards and 150 yards
Step-by-step explanation:
we know that
The <u><em>Triangle Inequality Theorem</em></u> states that the sum of any 2 sides of a triangle must be greater than the measure of the third side
Let
x ----> the possible lengths of the third hallway in yards
<em>Applying the Triangle Inequality Theorem</em>
1) 90+60 > x
150 > x
Rewrite
x < 150 yd
2) 60+x> 90
x > 90-60
x > 30 yd
The possible lengths of the third hallway in yards is the interval
(30,150)
All real numbers greater than 30 yards and less than 150 yards
therefore
between 30 yards and 150 yards
Answer: True
Step-by-step explanation:
Answer:(2,0)
Step-by-step explanation:
5x+2y=10
Verification of points
5(2)+2(0)=10
10=10
LHS=RHS
THUS solution is (2,0)
Answer:
(5sqrt(2), 45 deg)
(-5sqrt(2), 225 deg)
Step-by-step explanation:
(x,y)=(5,5)
So theta=arctan(5/5)=arctan(1)=45 degrees
Now r! r=sqrt(x^2+y^2)=sqrt(5^2+5^2)=sqrt(50)=sqrt(25)sqrt(2)=5sqrt(2)
So one polar point is (5sqrt(2) , 45 degrees)
Now if we do 180+45=225 degrees... this puts us in the 3rd quadrant... to get back to quadrant 1 we just take the opposite of our r
so another point is (-5sqrt(2) , 225 degrees)
