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3 years ago

CAN SOMEONE HELP ME PLEASEEE ?

Mathematics

1 answer:

zloy xaker [14]3 years ago

4 0

Answer:

D) 30

Step-by-step explanation:

1/2 in. = 3 ft.

5" = 10 x 1/2"

10 x 1/2" = 10 x 3'

5" = 30'

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2 years ago

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A worm is at the bottom of a 10ft hole. He starts climbing out of the hole, climbing 3 feet in one hour. Then he takes a break f

Korolek [52]

Answer:

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Step-by-step explanation:

7 0

3 years ago

Radioactive Decay:

Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

Answer: The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

Step-by-step explanation:

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

$k=\frac{0.693}{t_{1/2}}$

where,

$t_{1/2}$ = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

$k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}$

The formula used to calculate the time period for a first order reaction follows:

$t=\frac{2.303}{k}\log \frac{a}{(a-x)}$

where,

k = rate constant = $0.01506days^{-1}$

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

$t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days$

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0

2 years ago

-6x + 14 < -28 AND 3x + 28 < 25

trasher [3.6K]

Answer:

x>7

-6x+14< -28

-14. -14

-6x<-42

÷-6 ÷-6

x<7

switch signs because we divided by a negative number

x>7

Answer: x<-1

3x+28<25

-28 -28

3x<-3

÷3 ÷3

x<-1

7 0

3 years ago

Graph Ex+ 3y = 24 a. b. c. d.

8090 [49]

Answer:

(b)

Step-by-step explanation:

Given

$8x + 3y = 24$

Required

The graph

First, make y the subject

$3y = 24 - 8x$

Divide through by 3

$y = 8 - \frac{8}{3}x$

Let x = 3

$y = 8 - \frac{8}{3}*3 = 8 - 8 = 0$

Let x = 6

$y = 8 - \frac{8}{3}*6 = 8 - 16 = -8$

So, we plot the graph through

$(3,0)$ and $(6,-8)$

See attachment for graph

8 0

2 years ago