2. The integration region,

corresponds to what you might call an "annular sector" (i.e. the analog of circular sector for the annulus or ring). In other words, it's the region between the two circles of radii
and
, taken between the rays
and
. (The previous question of yours that I just posted an answer to has a similar region with slightly different parameters.)
You can separate the variables to compute the integral:

which should be doable for you. You would find it has a value of 19/72*(3√3 + 4π).
3. Without knowing the definition of the region <em>D</em>, the best we can do is convert what we can to polar coordinates. Namely,

so that

Answer:
yes
Step-by-step explanation:
Answer:
idk
Step-by-step explanation:
Answer option C
27x³+64y³
it's written as
(3x)³ +(4y)³
Now by using identify
<h3>a³+b³=(a+b)(a²-ab+b²)</h3>
(3x)³+(4y)³= (3x+4y){(3x)² - 3x*4y+(4y)²}
→ (3x+4y)( 9x²-12xy+16y²)
<u>So required answer is option C</u>
It will be 4 16 because it a circle on square timing 94 Fahrenheit