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3 years ago

How does the radius of the electron cloud compare to the radius of the nucleus?

Physics

1 answer:

Vadim26 [7]3 years ago

7 0

D. It is about 100,000 times larger.
A commonly used comparison is that of a pea in the middle of a racetrack.

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A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.7 1010 m (inside the orbit

Lubov Fominskaja [6]

Answer:

58515.9 m/s

Explanation:

We are given that

$d_1=4.7\times 10^{10} m$

$v_i=9.5\times 10^4 m/s$

$d_2=6\times 10^{12} m$

We have to find the speed (vf).

Work done by surrounding particles=W=0 Therefore, initial energy is equal to final energy.

$K_i+U_i=K_f+U_f$

$\frac{1}{2}mv^2_i-\frac{GmM}{d_1}=\frac{1}{2}mv^2_f-\frac{GmM}{d_2}$

$\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2}=\frac{1}{2}v^2_f$

$v^2_f=2(\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2})$

$v_f=\sqrt{2(\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2})}$

Using the formula

$v_f=\sqrt{v^2_i+2GM(\frac{1}{d_2}-\frac{1}{d_1})}$

$v_f=\sqrt{(9.5\times 10^4)^2+2\times 6.7\times 10^{-11}\times 1.98\times 10^{30}(\frac{1}{6\times 10^{12}}-\frac{1}{4.7\times 10^{10})}$

Where mass of sun= $M=1.98\times 10^{30} kg$

$G=6.7\times 10^{-11}$

$v_f=58515.9 m/s$

4 0

3 years ago

How do I do this?<br> Series and parallel circuits.

Svetlanka [38]

Connect the little light thingys to the top of the battery

8 0

3 years ago

Find the average value of position x, momentump, and square of the mometum p2 for the ground and first excited states of the par

nikdorinn [45]

Answer:

Explanation:

Find the average value of position x, momentump, and square of the mometum p2 for the ground and first excited states of the particle-in-a-box with mass m and box length L.

7 0

4 years ago

A woman drives 200 miles west and then turns south and drives 375 miles. Her trip takes her 11.75 hrs. What is the woman's avera

FromTheMoon [43]

Answer:

The woman's average velocity during the trip is 36.2 miles/hour.

Explanation:

Velocity can be define as the displacement of an object per time. It is a vector quantity, and measured in m/s.

i.e velocity = $\frac{displacement}{time}$

From the given question,

Displacement = $\sqrt{200^{2} + 375^{2} }$

= $\sqrt{40000+140625}$

= $\sqrt{180625}$

= 425

The displacement of woman is 425 miles.

velocity = $\frac{425}{11.75}$

= 36.1702 miles/hour

The woman's average velocity during the trip is 36.2 miles/hour.

7 0

3 years ago

Convert 15° C to fahrenheit and kelvin

vivado [14]

Answer:

59 degrees fahrenheit and 288.15 kelvin

Explanation:

4 0

3 years ago

Read 2 more answers