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3 years ago

What is significant about the primary colors of pigments?

Physics

1 answer:

ASHA 777 [7]3 years ago

8 0

A. They can be mixed together to make almost any other color.

Explanation:

The most significant thing about primary colors is that they can be mixed together to form any other colors. Primary colors are red, blue and green. These are the three primary colors of light.

Other colors can derived from primary colors when making pigments.
If the the three primary colors are mixed together, white color is produced.
Secondary colors are the other colors produced by combining any two primary colors of light.
Two colors the produce white when mixed are complementary colors.

Learn more:

Color vision brainly.com/question/5661389

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Can anyone help with this?

sleet_krkn [62]

Answer:

A. The volume of the object

Explanation:

First of all, it can only PROBABLY be A or D

But why is it only A?

Mass = The amount of matter in an object (nothing related here)
Volume = How much space is the object taking (super related here)

It's VOLUME here and not MASS here because:

It it would be Mass, then the object size could be anything, but the liquid wouldn't move as much higher.
But because it is Volume, it is taking space, which makes the liquid move
If the Mass would be the answer, then it would be totally not related, because mass isn't related over here, it matters about size.

<h2>Hence, A. The volume of the object </h2>

is your answer!!!!

4 0

2 years ago

Read 2 more answers

¿Qué nombre recibe un electrón que abandona el espacio interno del átomo dirigiéndose al exterior del átomo?

Alenkinab [10]

Answer:

i dont speack spanish sorry

Explanation: agian sorry

7 0

3 years ago

The drag force on a falling coffee filter can be modeled as a linear function with respect to velocity, F⃗ D =−bv, where b is a

nordsb [41]

Newton's second law and graphical analysis allow us to find the correct answer for the measure of the constant b is:

D) Stack several filters to change the mass measure the acceleration of the system.

Newton's second law establishes a relationship between the net force, the mass and the acceleration of the bodies.

∑ F = m a

Where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.

They indicate that the drag force on the filters is

F = - b v

Where b is a positive constant that depends on the shape and area of the filter and v is the speed of the filter.

Let's write Newton's second law.

W - fr = ma

W -bv = ma

In the experiment the students indicate that they can measure the position, velocity and acceleration of the body.

Based on the above, if we place several filter weights and measure their speed and acceleration in each case, we can make a graph of velocity versus acceleration, we can take the value of the constant b from the slope.

Let's analyze the different answers:

A) False. The constant b depends on the shape of the filter therefore it must be kept constant.

B) False. The constant depends on the area, so it must be kept constant.

C) May be. In this case, since we have the terminal velocity, the acceleration is zero, Newton's second law remains.

B v - W = 0

b = $\frac{W}{v}$

The problem with the method is the difficulty of measuring the compression terminal velocity.

D) True. According to the discussion of the velocity versus acceleration. graph, the constant b is equal to the slope of the graph.

E) May be. The problem with this method is finding a reliable value for the terminal velocity.

In conclusion, using Newton's second law and graphical analysis we can find the correct answer for the measure of the constant b is:

D) Stack several filters to change the mass measure the acceleration of the system.

Learn more here: brainly.com/question/2441565

6 0

2 years ago

A ball is thrown from a rooftop with an initial downward velocity of magnitude vo = 2.9 m/s. The rooftop is a distance above the

Step2247 [10]

Answer:

a) The velocity of the ball when it hits the ground is -20.5 m/s.

b) To acquire a final velocity of 27.3 m/s, the ball must be thrown from a height of 38 m.

Explanation:

I´ve found the complete question on the web:

<em />

<em>A ball is thrown from a rooftop with an initial downward velocity of magnitude v0=2.9 m/s. The rooftop is a distance above the ground, h= 21 m. In this problem use a coordinate system in which upwards is positive.</em>

<em>(a) Find the vertical component of the velocity with which the ball hits the ground.</em>

<em>(b) If we wanted the ball's final speed to be exactly 27, 3 m/s from what height, h (in meters), would we need to throw it with the same initial velocity?</em>

<em />

The equation of the height and velocity of the ball at any time "t" are the following:

h = h0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

h = height of the ball at time t.

h0 = initial height.

v0 = initial velocity.

t = time.

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).

v = velocity of the ball at a time "t".

First, let´s find the time it takes the ball to reach the ground (the time at which h = 0)

h = h0 + v0 · t + 1/2 · g · t²

0 = 21 m - 2.9 m/s · t - 1/2 · 9.8 m/s² · t²

Solving the quadratic equation using the quadratic formula:

t = 1.8 s ( the other solution of the quadratic equation is rejected because it is negative).

Now, using the equation of velocity, let´s find the velocity of the ball at

t = 1.8 s:

v = v0 + g · t

v = -2.9 m/s - 9.8 m/s² · 1.8 s

v = -20.5 m/s

The velocity of the ball when it hits the ground is -20.5 m/s.

b) Now we have the final velocity and have to find the initial height. Using the equation of velocity we can obtain the time it takes the ball to acquire that velocity:

v = v0 + g · t

-27.3 m/s = -2.9 m/s - 9.8 m/s² · t

(-27.3 m/s + 2.9 m/s) / (-9.8 m/s²) = t

t = 2.5 s

The ball has to reach the ground in 2.5 s to acquire a velocity of 27.3 m/s.

Using the equation of height, we can obtain the initial height:

h = h0 + v0 · t + 1/2 · g · t²

0 = h0 -2.9 m/s · 2.5 s - 1/2 · 9.8 m/s² · (2.5 s)²

-h0 = -2.9 m/s · 2.5 s - 1/2 · 9.8 m/s² · (2.5 s)²

h0 = 38 m

To acquire a final velocity of 27.3 m/s, the ball must be thrown from a height of 38 m.

6 0

4 years ago

What causes seasons to occur?

LUCKY_DIMON [66]

It’s C I hope it helps you

3 0

3 years ago

Read 2 more answers