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Allisa [31]
3 years ago
11

A woman drives 200 miles west and then turns south and drives 375 miles. Her trip takes her 11.75 hrs. What is the woman's avera

ge Velocity during the trip
Physics
1 answer:
FromTheMoon [43]3 years ago
7 0

Answer:

The woman's average velocity during the trip is 36.2 miles/hour.

Explanation:

Velocity can be define as the displacement of an object per time. It is a vector quantity, and measured in m/s.

i.e velocity = \frac{displacement}{time}

From the given question,

Displacement = \sqrt{200^{2} + 375^{2}  }

                       = \sqrt{40000+140625}

                       = \sqrt{180625}

                       = 425

The displacement of woman is 425 miles.

velocity = \frac{425}{11.75}

             = 36.1702 miles/hour

The woman's average velocity during the trip is 36.2 miles/hour.

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3. A worker pushes a box across the floor to the right at a constant speed with a force of 25N. What
WITCHER [35]

Answer:

Friction between the box and the floor is 25N to the left.

Explanation:

According to Newton's second law of motion, the net force acting on an object is equal to the produce between the object's mass and its acceleration:

F_{net}=ma

where

m is the mass of the object

a is its acceleration

In this problem, we have two forces acting on the object:

- The applied force, F = 25 N, to the right

- The force of friction F_f, opposing the motion of the box, so to the left

So we can write the net force as

F_{net}=F-F_f

Also, we know that the box is moving at constant speed: this means its acceleration is zero, so

a=0

Therefore

F_{net}=0

WHich means:

F-F_f=0

And therefore,

F_f=F=25 N

which means that the force of friction is also 25 N.

6 0
3 years ago
A 750-kg automobile is moving at 16.8 m/s at a height of 5.00 m above the bottom of a hill when it runs out of gasoline. The car
anygoal [31]

Answer:h=19.4 m

Explanation:

Given

mass of automobile m=750\ kg

Initial height of automobile h_o=5\ m

Velocity at this instant v=16.8\ m/s

If the car stops somewhere at a height h

Thus conserving total energy we get

K_i+U_i=K_f+U_f

\frac{1}{2}mv^2+mgh_o=\frac{1}{2}m(0)^2+mgh

\frac{v^2}{2g}+h_o=h

h=5+\frac{16.8^}{2\times 9.8}

h=5+14.4

h=19.4\ m

6 0
3 years ago
How much work will it take to lift a 2-kg pair of hiking boots 2 meters off the
AnnyKZ [126]

Answer:

Option C - 39.2 J

Explanation:

We are given that;

Mass; m = 2 kg.

Distance moved off the floor;d = 10 m.

Acceleration due to gravity;g = 9.8 m/s².

We want to find the work done.

Now, the Formula for work done is given by;

Work = Force × displacement.

In this case, it's force of gravity to lift up the boots, thus;

Formula for this force is;

Force = mass x acceleration due to gravity

Force = 2 × 9.8 = 19.2 N

∴ Work done = 19.6 × 2

Work done = 39.2 J.

Hence, the Work done to life the boot of 2 kg to a height of 2 m is 39.2 J.

7 0
3 years ago
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superman is flying 54.5 m/s when he sees a train about to fall into a river 850 m away . he must reach the train in 4.22 s
IRISSAK [1]

Answer:

What is the question?

Explanation:

8 0
3 years ago
If you are following a car and also being tailgated by another vehicle, your best option would be to.. a. Increase the following
Pie

Answer:

Your answer here is D

Explanation:

Slowly pressing your breaks will help ensure you are not hit by the other car. If they hit you its their fault. Hope this helps :)!

7 0
3 years ago
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