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Allisa [31]
3 years ago
11

A woman drives 200 miles west and then turns south and drives 375 miles. Her trip takes her 11.75 hrs. What is the woman's avera

ge Velocity during the trip
Physics
1 answer:
FromTheMoon [43]3 years ago
7 0

Answer:

The woman's average velocity during the trip is 36.2 miles/hour.

Explanation:

Velocity can be define as the displacement of an object per time. It is a vector quantity, and measured in m/s.

i.e velocity = \frac{displacement}{time}

From the given question,

Displacement = \sqrt{200^{2} + 375^{2}  }

                       = \sqrt{40000+140625}

                       = \sqrt{180625}

                       = 425

The displacement of woman is 425 miles.

velocity = \frac{425}{11.75}

             = 36.1702 miles/hour

The woman's average velocity during the trip is 36.2 miles/hour.

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Answer:

The  correct option is  H

Explanation:

From the question we are told that

    The index of refraction of  coating is  n_1

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Generally the condition for constructive for a thin film interference is mathematically represented

            2 *  t  = [ m  + \frac{1}{2}] \frac{\lambda}{n_1 }

Here  t represents the thickness

For minimum thickness  m =  0

So

           2 *  t  =0  + \frac{1}{2}\frac{\lambda}{n_1 }

=>        t  =\frac{\lambda}{4n_1 }

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3 years ago
Which of the following is not a type of system?
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Social Classical is not a type of system.
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It is easier to lift the load as the load is pushed towards the wheel in a wheelbarrow​
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Two equal charges with magnitude Q and Q experience a force of 12.3442 when held at a distance r. What is the force between two
andre [41]

Answer:

197.5072.

Explanation:

According to the Coulomb's law, the magnitude of the electrostatic force of interaction between two charges \rm q_1 and \rm q_2 which are separated by the distance \rm d is given by

\rm F = \dfrac{kq_1q_2}{d^2}.

<em>where,</em> k is the Coulomb's constant.

For the case, when,

  • \rm q_1 = Q.
  • \rm q_2 = Q.
  • \rm d=r.
  • \rm F=12.3442.

Then, using Coulomb's law,

\rm 12.3442 = \dfrac{kQQ}{r^2}=\dfrac{kQ^2}{r^2}\ \ \ \ .......\ (1).

For the case, when,

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  • \rm q_2 = 2Q.
  • \rm d=\dfrac r2.

Then, using Coulomb's law, the new electric force between the charges is given by,

\rm F' = \dfrac{k(2Q)(2Q)}{\left (\dfrac r2\right )^2}\\=\dfrac{k\ 4Q^2}{\dfrac{r^2}{4}}\\=4\times 4 \times \dfrac{kQ^2}{r^2}\\=16\ \dfrac{kQ^2}{r^2}\\=16\times 12.3442\ \ \ \ \ \ \ \ (Using\ (1))\\=197.5072.

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True or False:
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True. The object's location is based off of the reference point, so by moving the reference point, you move the object's location.

Explanation:

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