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ivolga24 [154]
3 years ago
12

Convert 15° C to fahrenheit and kelvin

Physics
2 answers:
earnstyle [38]3 years ago
5 0

Answer:

59 oF and 288 K

Explanation:

oF= 15 x 1.8 + 32= 59

K= 15+273 = 288

vivado [14]3 years ago
4 0

Answer:

59 degrees fahrenheit and 288.15 kelvin

Explanation:

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Bezzdna [24]

Explanation:

A. answer is the correct answer

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4 years ago
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A car travels from point A to point B, moving in the same direction but with a non-constant speed. The first half of the distanc
Dmitrij [34]

Answer:

Explanation:

From A to B

distance traveled with velocity v_1  in time t_1

\frac{d}{2}=v_1t_1----1

from B to C

distance traveled is 0.5 d with v_2  and v_3  velocity for half-half time

\frac{d}{2}=\frac{v_2t_2}{2}+\frac{v_3t_3}{2}----2

divide 1 and 2 we get

\frac{1}{1}=\frac{2v_1t_1}{v_2t_2+v_3t_3}

\frac{t_1}{t_2}=\frac{v_2+v_3}{2v_1}

Now average velocity is given by

v_{avg}=\frac{d}{t_1+t_2}

taking t_1  common

v_{avg}=\frac{2v_1t_1}{t_1(1+\frac{t_2}{t_1})}

v_{avg}=\frac{2v_1}{1+\frac{2v_1}{v_2+v_3}}

v_{avg}=\frac{2v_1(v_2+v_3)}{2v_1+v_2+v_3}  

6 0
4 years ago
A beam of light has a wavelength of 620 nm in vacuum.
crimeas [40]

Explanation:

It is given that,

Wavelength of a beam of light in vacuum, \lambda_o=620\ nm

(a) Let v is the speed of light in a liquid whose index of refraction at this wavelength is 1.56.

We know that,

Refractive index,

n=\dfrac{c}{v}\\\\v=\dfrac{c}{n}\\\\v=\dfrac{3\times 10^8}{1.56}\\\\v=1.92\times 10^8\ m/s

(b) The wavelength of light in material,

\lambda=\dfrac{\lambda_o}{n}

Let \lambda_1 is the wavelength of these waves in the liquid. So,

\lambda_1=\dfrac{\lambda_o}{n}\\\\\lambda_1=\dfrac{620\times 10^{-9}}{1.56}\\\\\lambda_1=3.97\times 10^{-7}\ m

Hence, this is the required solution.

7 0
4 years ago
A seated cable row is an example of which level of training in the NASM OPT model?
Vera_Pavlovna [14]

Answer:

B. Strength

Explanation:

The OPT Model, or Optimum Performance Training Model, is a "fitness training system created by the NASM. The OPT Model is contructed with scientific evidence and principles that progresses an individual through five training phases: stabilization endurance, strength endurance, hypertrophy, maximal strength and power".

On the stabilization level we have the phase 1 called stabilization endurance.

For the level strength part we have 3 phases . Phase 2: Strength endurance , Phase 3: Hypertrophy, Phase 4: Maximal strength. And we can consider the case "A seated cable row" on this the level strength since we need to have some abilities to do this but not enough to stay on the power level since this one is the advancd level.

For the power level we have the last phase called power in order to mantain and conduct high training level programs.

8 0
4 years ago
WILL GIVE BRAINLIEST!!
Rudiy27

Answer:

B. NEWTONS SECOND LAW

Explanation:

I believe

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3 years ago
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