Ted bought a new book for $20.00. If the sales tax was 8%, how much did Ted play in all for the books?

1 answer:

5 0

I believe what you would do is multiply $20 by 8% and get 1.6. So ten you would subtract 1.6 from 20 and get $18.40 on the book.

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Elodia [21]

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5 0

3 years ago

2 Polhts

Arada [10]

<h3>Answers: B and C</h3><h3>Acceleration and velocity</h3>

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Explanation:

Distance is a scalar. It's simply a single number. It does not include a direction. We can rule out choice A. If you wanted direction connected to distance, then it would form a displacement vector.

Acceleration is a vector because velocity is a vector, and vice versa. The two are tied together. The acceleration is the change in velocity. You can think of it as acceleration = velocity/time.

Speed is not a vector. It's a single value just like distance is. If you want to have speed tied to a direction, then you would form a velocity vector.

5 0

3 years ago

The compound interest on a sum of money in

Yakvenalex [24]

Answer:

The difference between the principal and the compound interest in three years is Rs 17,994

Step-by-step explanation:

The compound interest is given according to the following formula;

$C.I. = P \cdot \left ( 1 + \dfrac{r}{n} \right ) ^{n\cdot t} - P$

The given amount of the compound after 2 years = Rs 5,460

The given amount of the compound after 4 years = Rs 12,066.60

Therefore, we have;

$5,460 = P \cdot \left ( 1 + \dfrac{r}{100} \right ) ^{2} - P$ ...(1)

$12,066.60 = P \cdot \left ( 1 + \dfrac{r}{100} \right ) ^{4} - P$ ...(2)

Dividing equation (2) by (1), we have;

$\dfrac{12,066.60}{5,460} = \dfrac{P \cdot \left ( \left ( 1 + \dfrac{r}{100} \right ) ^{4} - 1\right )}{P \cdot \left (\left ( 1 + \dfrac{r}{100} \right ) ^{2} -1 \right ) } =\dfrac{\left ( 1 + \dfrac{r}{100} \right ) ^{4} - 1}{\left ( 1 + \dfrac{r}{100} \right ) ^{2} -1 }$

$Let \ \left ( 1 + \dfrac{r}{100} \right ) ^{2} = x, we \ get;$

$\dfrac{12,066.60}{5,460} =\dfrac{\left ( 1 + \dfrac{r}{100} \right ) ^{4} - 1}{\left ( 1 + \dfrac{r}{100} \right ) ^{2} -1 } = \dfrac{x^2 - 1}{x - 1}$