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Alona [7]
3 years ago
5

You put $500 in the bank for 2 years with a 3.2% interest rate. How much Interest is earned?

Mathematics
1 answer:
kvv77 [185]3 years ago
5 0

Answer:1.0%

Step-by-step explanation:

hopes it help

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15/9 =25/9x<br><br> I simplified it as much as I could but i'm stuck here:/
kvv77 [185]

Answer:

Step-by-step explanation:

We move all terms to the left: 15/9-(25/9x)=0 Domain of the equation: 9x)!=0 x!=0/1 x!=0 x∈R

We add all the numbers together, and all the variables

-(+25/9x)+15/9=0

We get rid of parentheses

-25/9x+15/9=0

We calculate fractions

=0 x=0/1 x=0

i hope helps you and if you want you can give me a brainly crown only if you want

4 0
3 years ago
Read 2 more answers
Express .05 as a fraction in similest form
Alja [10]

0.05 = 5% = 5/100

Simplify 5/100 and you get 1/20.


Hope this helps & good luck. :)

5 0
3 years ago
Read 2 more answers
What is the lmc of two numbers that have no common factors greater then 1
Luba_88 [7]
We can take prime numbers so they don't have a common factor other than 1.

3, and 5.

So we have to list the multiples to find the LCM

3: 3, 6, 9, 12, 15, 18
5: 5, 10, 15, 20, 25

15 is the LCM of 3 and 5

So, you can notice that if two numbers, lets call them a and b, have no common factor, then a \times b is the LCM.

Hope that helped :)

6 0
3 years ago
Suppose you earned $15 from your job last week. You want to save $3 and buy some books that cost $4 each. To find how many books
vova2212 [387]

Answer:

You can buy 3 books 4 x 3 = 12

Step-by-step explanation:

8 0
3 years ago
Find an equation of the plane orthogonal to the line
jolli1 [7]

The given line is orthogonal to the plane you want to find, so the tangent vector of this line can be used as the normal vector for the plane.

The tangent vector for the line is

d/d<em>t</em> (⟨0, 9, 6⟩ + ⟨7, -7, -6⟩<em>t </em>) = ⟨7, -7, -6⟩

Then the plane that passes through the origin with this as its normal vector has equation

⟨<em>x</em>, <em>y</em>, <em>z</em>⟩ • ⟨7, -7, -6⟩ = 0

We want the plane to pass through the point (9, 6, 0), so we just translate every vector pointing to the plane itself by adding ⟨9, 6, 0⟩,

(⟨<em>x</em>, <em>y</em>, <em>z</em>⟩ - ⟨9, 6, 0⟩) • ⟨7, -7, -6⟩ = 0

Simplifying this expression and writing it standard form gives

⟨<em>x</em> - 9, <em>y</em> - 6, <em>z</em>⟩ • ⟨7, -7, -6⟩ = 0

7 (<em>x</em> - 9) - 7 (<em>y</em> - 6) - 6<em>z</em> = 0

7<em>x</em> - 63 - 7<em>y</em> + 42 - 6<em>z</em> = 0

7<em>x</em> - 7<em>y</em> - 6<em>z</em> = 21

so that

<em>a</em> = 7, <em>b</em> = -7, <em>c</em> = -6, and <em>d</em> = 21

4 0
3 years ago
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