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Gennadij [26K]
3 years ago
11

I know the answer is .78, but don’t understand why? .9-.6X.2

Mathematics
2 answers:
dangina [55]3 years ago
7 0

Step-by-step explanation:

When you multiply 0.6 and 0.2, you do not get 1.2. Rather, the product would be 0.12.

We have the equation 0.9-(0.6)(0.2)

To show you what is happening, lets convert these numbers into fractions

This would give us \frac{9}{10} -(\frac{6}{10})(\frac{2}{10})

Recall that when you multiply two fractions, you multiply the numerators and denominators separately. Doing so gives us

\frac{9}{10} -\frac{6*2}{10*10}

Which then becomes

\frac{9}{10} -\frac{12}{100}

The last thing we need to do is to create a common denominator

\frac{90}{100}-\frac{12}{100}=\frac{78}{100} =0.78

Another way to see what is happening is by thinking about the numbers in scientific notation. Doing so would give us

9*10^{-1}-(6*10^{-1})(2*10^{-1})

Once we multiply these terms, we get

9*10^{-1}-6*10^{-1}*2*10^{-1}\\\\9*10^{-1}-12*10^{-2}

Now we can convert these numbers into decimals to get

0.9-0.12=0.78

ladessa [460]3 years ago
6 0
0.6 x 0.2 = 12 and .9 - .12 = .78

It may be confusing because the decimals aren’t like whole numbers.
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Could the inverse of a non-function be a function? Explain or give an example.
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Answer:

The inverse of a non-function mapping is not necessarily a function.

For example, the inverse of the non-function mapping \lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\! is the same as itself (and thus isn't a function, either.)

Step-by-step explanation:

A mapping is a set of pairs of the form (a,\, b). The first entry of each pair is the value of the input. The second entry of the pair would be the value of the output.  

A mapping is a function if and only if for each possible input value x, at most one of the distinct pairs includes x\! as the value of first entry.

For example, the mapping \lbrace (0,\, 0),\, (1,\, 0) \rbrace is a function. However, the mapping \lbrace (0,\, 0),\, (1,\, 0),\, (1,\, 1) \rbrace isn't a function since more than one of the distinct pairs in this mapping include 1 as the value of the first entry.

The inverse of a mapping is obtained by interchanging the two entries of each of the pairs. For example, the inverse of the mapping \lbrace (a_{1},\, b_{1}),\, (a_{2},\, b_{2})\rbrace is the mapping \lbrace (b_{1},\, a_{1}),\, (b_{2},\, a_{2})\rbrace.

Consider mapping \lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!. This mapping isn't a function since the input value 0 is the first entry of more than one of the pairs.

Invert \lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\! as follows:

  • (0,\, 0) becomes (0,\, 0).
  • (0,\, 1) becomes (1,\, 0).
  • (1,\, 0) becomes (0,\, 1).
  • (1,\, 1) becomes (1,\, 1).

In other words, the inverse of the mapping \lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\! would be \lbrace (0,\, 0),\, (1,\, 0),\, (0,\, 1),\, (1,\, 1) \rbrace\!, which is the same as the original mapping. (Mappings are sets. There is no order between entries within a mapping.)

Thus, \lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\! is an example of a non-function mapping that is still not a function.

More generally, the inverse of non-trivial ellipses (a class of continuous non-function \mathbb{R} \to \mathbb{R} mappings, including circles) are also non-function mappings.

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d. 43,024 cal = 43,024·4.184 J = 180,012 J = 180.012 kJ

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