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3 years ago

_____ + 5 3/4 = 9 5/8please help you will get 75 points

Mathematics

2 answers:

LuckyWell [14K]3 years ago

7 0

Answer:

3 7/8

Step-by-step explanation:

_____ + 5 3/4 = 9 5/8

x + 5 3/4 = 9 5/8

Subtract 5 3/4 from each side

x + 5 3/4 - 5 3/4 = 9 5/8 - 5 3/4

x = 9 5/8 - 5 3/4

Get a common denominator of 8

5 3/4 *2/2 = 5 6/8

x = 9 5/8 - 5 6/8

We need to borrow 1 from the 9 in the form of 8/8

x= 8 + 8/8+ 5/8 - 5 6/8

x = 8 13/8 - 5 6/8

= 3 7/8

andrey2020 [161]3 years ago

4 0

Answer:

$\Large \boxed{3\frac{7}{8}}$

Step-by-step explanation:

Let the missing value be x.

$x+5\frac{3}{4} =9 \frac{5}{8}$

Subtract $5 \frac{3}{4}$ from both sides.

$x =9 \frac{5}{8} - 5 \frac{3}{4}$

Converting the mixed fractions to improper fractions.

$x =\frac{77}{8} - \frac{23}{4}$

Make denominators equal and subtract.

$x =\frac{77}{8} - \frac{46}{8}$

$x =\frac{77-46}{8}$

$x =\frac{31}{8}$

Converting the improper fraction into a mixed fraction.

$x=3\frac{7}{8}$

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Answer:

Step-by-step explanation:

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3 0

3 years ago

Long Division: (3x^4-8x^3-x^2+9x+5) / (x-2) pleaseee answer this

Drupady [299]

3x⁴ = 3x³ • x, and

3x³ (x - 2) = 3x⁴ - 6x³

Subtract this from the numerator to get a remainder of

(3x⁴ - 8x³ - x² + 9x + 5) - (3x⁴ - 6x³) = -2x³ - x² + 9x + 5

-2x³ = -2x² • x, and

-2x² (x - 2) = -2x³ + 4x²

Subtract this from the previous remainder to get a new remainder of

(-2x³ - x² + 9x + 5) - (-2x³ + 4x²) = -5x² + 9x + 5

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Subtract this from the last remainder to get a new one of

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This gives a new remainder of

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3 does not divide x, so we're done.

So, we have

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3 years ago

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2 years ago

Radioactive Decay:

Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

Answer: The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

Step-by-step explanation:

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

$k=\frac{0.693}{t_{1/2}}$

where,

$t_{1/2}$ = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

$k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}$

The formula used to calculate the time period for a first order reaction follows:

$t=\frac{2.303}{k}\log \frac{a}{(a-x)}$

where,

k = rate constant = $0.01506days^{-1}$

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

$t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days$

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

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3 years ago

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3 years ago

Read 2 more answers

_____ + 5 3/4 = 9 5/8please help you will get 75 points​

_____ + 5 3/4 = 9 5/8please help you will get 75 points