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Leya [2.2K]
3 years ago
10

-3.25 as a mixed number

Mathematics
1 answer:
EastWind [94]3 years ago
3 0

Answer:

Step-by-step explanation:

You can read it as :Minus three and one fourth

Or minus thirteen fourths

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How do you multiply(2x+3)(x-7)
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Answer:

2x(x-7)+3(x-7)

2x²-14x+3x-21

2x²-11x-21

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3 years ago
What must be a factor of the polynomial function f(x) graphed on the coordinate plane below?
vesna_86 [32]

Answer:

x+2

Step-by-step explanation:

we know that

To find out the factors of a polynomial, determine the x-intercepts or zeros of the polynomial

Remember that

The x-intercepts of a polynomial are the values of x when the value of the polynomial is equal to zero

In this problem

Looking at the graph

For x=-2, f(x)=0

so

x=-2 is an x-intercept or zero of the polynomial

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adds 2 both sides

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3 years ago
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. Determine whether the vectors (5, −2, 4), (2, −3, 5), and (4, 5−
Tems11 [23]

Answer: The vectors are linearly dependent.

The solution is in the attachment

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3 years ago
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What adds to get 15 and multiplies to get negative 20
kakasveta [241]
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5 0
3 years ago
Match the following items.
max2010maxim [7]

Answer:

1. ∠ABD = 20°.

2.  Arc AB =  140°.

3.  Arc AD =  40°.

Step-by-step explanation:

Given information: ∠ADB = 70°. BD is diameter.

According to Central angle theorem, the central angle from two chosen points A and B on the circle is always twice the inscribed angle from those two points.

By Central angle theorem,

\angle DAB=90^{\circ}

Using angle sum of property in triangle ADB we get,

\angle ADB+\angle DAB+\angle  ABD=180^{\circ}

70^{\circ}+90^{\circ}+\angle  ABD=180^{\circ}

\angle  ABD=20^{\circ}.

Draw a line segment AO.

In triangle AOD, AO=OD, so

\angle ODB=\angle OAD=70^{\circ}

Using angle sum property in triangle AOD,

\angle AOD+\angle ODA+\angle  OAD=180^{\circ}

\angle AOD+70^{\circ}+70^{\circ}=180^{\circ}

\angle AOD=40^{\circ}

Therefore length of arc AD is 40°.

The angle AOD and AOB are supplementary angles.

\angle AOD+\angle AOB=180^{\circ}

40^{\circ}+\angle AOB=180^{\circ}

\angle AOB=140^{\circ}

Therefore length of arc AB is 140°.

3 0
3 years ago
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