1/3(x-6)=16 Please help me out

A population of rabbits in a lab, p(x), can be modeled by the function p(x) = 20(1.014)x , where x represents the number of days

Nitella [24]

Answer:

20 = initial population of the rabbits

1.014 = growth rate of the rabbits

the average rate of change from day 50 to day 100 is 0.8

Step-by-step explanation:

A population of rabbits in a lab, p(x), can be modeled by the function

p(x) = 20(1.014)^x

This model is exponential. Where 20 = initial population of the rabbits

1.014 = growth rate of the rabbits with 1.4% increase rate of the rabbits

To find the average rate of change from day 50 to day 100,

find the population p(50) and p(100). Subtract them and divide by 100 - 50 = 50.

p(50) = 20(1.014)50 = 40.08...

p(100) = 20(1.014)100 = 80.32...

(80.32 - 40.08) / (100 - 50) = 40.24/50 = 0.8048. which is approximately 0.8 to the nearest tenth.

The rate of change is 0.8.

7 0

3 years ago

4{3sqaured+4(116-8(2×8))} I need to know ASAP it 9:30 where I live pls hwlp

inysia [295]

Start with 8*2=16
116-8= 108
108(16)=1728
3^2+4=13 13(1728)=22464
4(22464)=89856
The answer is 89,856

3 0

3 years ago

Multiplying Polynomials// Multiply- 12x^4 (-5/6x^3y^2)

ElenaW [278]

$12 x^{4} * (- \frac{5}{6} x^{3} y^{2})$
Now multiple the coefficients and add the exponents with common bases
$12 * - \frac{5}{6} = -10 \\ x^{4} + x^{3} = x^{7}$
Now write your final expression
$-10 x^{7} y^{3}$
Hope I helped!

6 0

3 years ago

A random sample of 144 recent donations at a certain blood bank reveals that 81 were type A blood. Does this suggest that the ac

Reptile [31]

Answer:

Null hypothesis: $p=0.4$

Alternative hypothesis: $p \neq 0.4$

$z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98$

$p_v =2*P(z>3.98)=0.0000689$

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

Step-by-step explanation:

Information given

n=144 represent the random sample taken

X=81 represent the number of people with type A blood

$\hat p=\frac{81}{144}=0.5625$ estimated proportion of people with type A blood

$p_o=0.4$ is the value that we want to verify

$\alpha=0.01$ represent the significance level

z would represent the statistic

$p_v{/tex} represent the p value Hypothesis to testWe want to test if the percentage of the population having type A blood is different from 40%.: Null hypothesis:[tex]p=0.4$

Alternative hypothesis: $p \neq 0.4$

the statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98$

Now we can calculate the p value with this probability taking in count the alternative hypothesis:

$p_v =2*P(z>3.98)=0.0000689$

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

3 0

3 years ago

Solve for 5x - 7 + 2x = 21 Help this will be very much appreciated .

dexar [7]

Answer:

x = 4

Step-by-step explanation:

Pull out like factors: 7x - 28 = 7 • (x - 4)

Solve: x-4 = 0

Add 4 to both sides of the equation: x = 4

Please mark as brainliest.

Thanks!

6 0

3 years ago

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