All categories

3 years ago

1/3(x-6)=16 Please help me out

Mathematics

2 answers:

Alexeev081 [22]3 years ago

6 0

Answer:

$\frac{1}{3} (x - 6) = 16) \times 3 \\ x - 6 = 3 \times 16 \\ x = 48 + 6 \\ \color{yellow} \boxed{ x = 54}$

arsen [322]3 years ago

6 0

Answer:

x=54

Step-by-step explanation:

i used a app its great and best for these types of questions

You might be interested in

Find the pattern of 1,2,6,18 and state if its arithmetic or geometric

Gnesinka [82]

Answer:

its a geometric sequence where each term is 3 times the previous term.

Step-by-step explanation:

{2,6,18,54,162,486,1458...}

6 0

2 years ago

Solve by completing the square and hunt for twice the larger root. x^2-9x+3=0

photoshop1234 [79]

Answer:

here is some answers and for you to understand it k

Step-by-step explanation:

Download pdf

8 0

3 years ago

Read 2 more answers

- 6.5 ( n - 5 )= 18.2

d1i1m1o1n [39]

Answer:

N=11/5

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

What are the zeros of the function f(x) = x^2 + 2x- 8 / x^2 - 2x - 8

Veronika [31]

Answer:

x=-4 and x=2

Step-by-step explanation:

You are given the function

$f(x)=\dfrac{x^2+2x-8}{x^2-2x-8}$

The zeros of the function are those value of x, for which $f(x)=0$

First, find x for which function is undefined

$x^2-2x-8\neq0\\ \\x^2-4x+2x-8\neq 0\\ \\x(x-4)+2(x-4)\neq 0\\ \\(x-4)(x+2)\neq 0\\ \\x\neq 4\text{ and }x\neq -2$

Now find points at which f(x)=0:

$f(x)=0\Rightarrow x^2+2x-8=0\\ \\x^2+4x-2x-8=0\\ \\x(x+4)-2(x+4)=0\\ \\(x-2)(x+4)=0\\ \\x=2\text{ or }x=-4$

For both these values (x=-4 and x=2) function f(x) is defined, then x=-4 and x=2 are zeros of the function.

7 0

3 years ago

Read 2 more answers

HELP ME PLEASEEEEEEEEEEEEE

kakasveta [241]

Bro we cant help you, there must be a kind of image before that question. You have to attach it since we dont know what “Organism A and B” are.. we dont know what its referring to so you might have to repost this question again

3 0

3 years ago