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kotegsom [21]
3 years ago
5

f(x) = 7x g(x) = 7x + 6 Which statement about f(x) and its translation, g(x), is true? The domain of g(x) is {x | x > 6}, and

the domain of f(x) is {x | x > 0}. The domain of g(x) is {y | y > 0}, and the domain of f(x) is {y | y > 6}. The asymptote of g(x) is the asymptote of f(x) shifted six units down. The asymptote of g(x) is the asymptote of f(x) shifted six units up.
Mathematics
2 answers:
Cloud [144]3 years ago
7 0
The asymptote of g(x) is the aymptote of f(x) shifted six units up
Oksanka [162]3 years ago
5 0

Answer:

The correct option is 4. The asymptote of g(x) is the asymptote of f(x) shifted six units up.

Step-by-step explanation:

The given functions are

f(x)=7x

g(x)=7x+6

Both are linear function and the domain of a linear function is all real real numbers.

Domain of f(x) = {x | x∈R }

Domain of g(x) = {x | x∈R }

Therefore option 1 and 2 are incorrect.

The linear asymptote of a linear function f(x)=mx+b is

y=mx+b+\delta x

Where, δx is infinitely small number, but not quite equal to 0.

The asymptote of f(x) is

y=7x+\delta x

The asymptote of g(x) is

y=7x+6+\delta x

It means the asymptote of f(x) shifts six units up to get the asymptote of g(x).

Therefore option 4 is correct. The asymptote of g(x) is the asymptote of f(x) shifted six units up.

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Rewrite as an exponential equation Inx=6
butalik [34]

Answer: x=e^6

Step-by-step explanation:

Rearrange, know that ln = e

4 0
3 years ago
Read 2 more answers
Given that (ax^2 + bx + 3) (x + d) = x^3 + 6x^2 + 11x + 12<br> a + 2b - d = ?
Mariulka [41]

Answer:

Let's solve for a.

(ax2+bx+3)(x+d)=x3+6x2+11x+12a+2b−d

Step 1: Add -12a to both sides.

adx2+ax3+bdx+bx2+3d+3x+−12a=x3+6x2+12a+2b−d+11x+−12a

adx2+ax3+bdx+bx2−12a+3d+3x=x3+6x2+2b−d+11x

Step 2: Add -bdx to both sides.

adx2+ax3+bdx+bx2−12a+3d+3x+−bdx=x3+6x2+2b−d+11x+−bdx

adx2+ax3+bx2−12a+3d+3x=−bdx+x3+6x2+2b−d+11x

Step 3: Add -bx^2 to both sides.

adx2+ax3+bx2−12a+3d+3x+−bx2=−bdx+x3+6x2+2b−d+11x+−bx2

adx2+ax3−12a+3d+3x=−bdx−bx2+x3+6x2+2b−d+11x

Step 4: Add -3d to both sides.

adx2+ax3−12a+3d+3x+−3d=−bdx−bx2+x3+6x2+2b−d+11x+−3d

adx2+ax3−12a+3x=−bdx−bx2+x3+6x2+2b−4d+11x

Step 5: Add -3x to both sides.

adx2+ax3−12a+3x+−3x=−bdx−bx2+x3+6x2+2b−4d+11x+−3x

adx2+ax3−12a=−bdx−bx2+x3+6x2+2b−4d+8x

Step 6: Factor out variable a.

a(dx2+x3−12)=−bdx−bx2+x3+6x2+2b−4d+8x

Step 7: Divide both sides by dx^2+x^3-12.

a(dx2+x3−12)

dx2+x3−12

=

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

a=

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

Answer:

a=

−bdx−bx2+x3+6x2+2b−4d+8x/

dx2+x3−12

Step-by-step explanation:

8 0
3 years ago
Need help thanks I'll mark brainliest
sukhopar [10]

Answer:

m∠ACD = 40°

Step-by-step explanation:

(4x + 2) + (6x - 12) = 8x,

10x - 10 = 8x,

2x = 10,

x = 5

8(5) = 40°

8 0
3 years ago
PLEASE HELP I HAVE 6 MINUTES LEFT!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
lord [1]

Answer:the answer is D

Step-by-step explanation:

4 0
3 years ago
The Gotemba walking trail up Mount Fuji is about 9km long. Walkers need to return from the 18km walk by 8pm. Toshi estimates tha
stiv31 [10]

Answer:

Toshi must begin his walk at 11:00 AM in order that he can return by 8:00 PM.

Step-by-step explanation:

Since the Gotemba walking trail up Mount Fuji is about 9km long, and walkers need to return from the 18km walk by 8pm, if Toshi estimates that he can walk up the mountain at 1.5km / h on average, and down at twice that speed , these speeds taking into account meal breaks and rest times, to determine what is the latest time he can begin his walk so that he can return by 8pm the following calculation must be performed:

Climb: 1.5 km / h

Descent: 2 x 1.5 km / h = 3 km / h

Climb: 9 km / 1.5 km / h = 6 hours

Descent: 9km / 3 km / h = 3 hours

Total: 9 hours

8 PM = 20:00

20:00 - 09:00 = 11:00

Thus, Toshi must begin his walk at 11:00 AM in order that he can return by 8:00 PM.

3 0
3 years ago
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