<u>Answer:</u> The volume of oxygen gas is 91.4 L.
<u>Explanation:</u>
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
......(1)
Given mass of ethanol = 38.5 g
Molar mass of ethanol = 46 g/mol
Plugging values in equation 1:

The given chemical equation follows:

By stoichiometry of the reaction:
If 1 mole of ethanol produces 3 moles of water
So, 0.840 moles of ethanol will produce =
of water
The ideal gas equation is given as:
.......(2)
where
P = pressure = 1.75 atm
V = volume of oxygen gas = ?
n = number of moles= 2.52 moles
R = Gas constant = 0.0821 L.atm/mol.K
T = temperature of the tank = ![500^oC=[500+273]K=773K](https://tex.z-dn.net/?f=500%5EoC%3D%5B500%2B273%5DK%3D773K)
Putting values in equation 2, we get:

Hence, the volume of oxygen gas is 91.4 L.