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bogdanovich [222]
2 years ago
9

6Most types of heather grow better in acidic soil.

Chemistry
1 answer:
lana66690 [7]2 years ago
3 0

Answer:

Its a and e

Explanation:

So ez give me brainliest nd a thanks plz

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When Niels Bohr refined the model of an atom,what new idea did he include?
pshichka [43]

Answer:

Niels Bohr, refined the model of an atom by proposing a quantized shell structure atomic model in order to describe how the electrons are able to maintain stable orbits around the nucleus

Based on the predictions of classical mechanics the electron motion of the Rutherford model was unstable as the electrons where expected to have lost some energy during motion and thus having to come rest in the nucleus

According to the modification by Neils Bohr in 1913, electrons move in  shells or orbits of fixed energy and emission of electromagnetic radiation takes place only when electrons changes the orbit in which they move

Explanation:

5 0
3 years ago
How many half lives would pass if a mass of copper-66 decayed for 51 minutes? The half life of Cu-66 is 5.10 minutes.
Sveta_85 [38]
Divide 51 by 5.1, it's 10 half lives
4 0
3 years ago
How do I find the molar mass of Copper (II) Nitrate?
QveST [7]

Answer:

The molar mass of copper (II) nitrate is 187.5 g/mol.

Explanation:

The molar mass is the mass of all the atoms in a molecule in grams per mole. To calculate the molar mass of a molecule, we first obtain the atomic weights from the individual elements in a periodic table. We then count the number of atoms and multiply it by the individual atomic masses.

8 0
3 years ago
Which is the correct formula for phosphorus pentachloride?
klio [65]

PCl5

hope this helps

have a wonderful day

5 0
3 years ago
Read 2 more answers
Using the equations 2 Sr(s) + O₂ (g) → 2 SrO (s) ∆H° = -1184 kJ/mol SrO (s) + CO₂ (g) → SrCO₃ (s) ∆H° = -234 kJ/mol CO₂ (g) → C(
kkurt [141]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is 72 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

2SrCO_3(s)\rightarrow 2Sr(s)+2C(s)+3O_2(g)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) 2Sr(s)+O_2(g)\rightarrow 2SrO(s)    \Delta H_1=-1184kJ

(2) SrO(s)+CO_2(g)\rightarrow SrCO_3(s)     \Delta H_2=-234kJ      ( × 2)

(3) CO_2(g)\rightarrow C(s)+O_2(g)     \Delta H_3=394kJ    ( × 2)

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[2\times (-\Delta H_2)]+[2\times (\Delta H_3)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-1184))+(2\times -(-234))+(2\times (394))]=72kJ

Hence, the \Delta H^o_{rxn} for the reaction is 72 kJ.

4 0
3 years ago
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