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bogdanovich [222]
2 years ago
9

6Most types of heather grow better in acidic soil.

Chemistry
1 answer:
lana66690 [7]2 years ago
3 0

Answer:

Its a and e

Explanation:

So ez give me brainliest nd a thanks plz

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Why are the chemicals in the water turning the phrogs gay?
Liula [17]

Answer:

Yes

Explanation:

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3 years ago
How many gram-atoms are in 120-gram sample of calcium metal? How many atoms is this?
Elden [556K]
(sample g/1) X (1 mole/40.078(MW of Ca)) = moles of sample (moles of sample)(6.022 x 10^23( no of atoms)/ 1 mole) = # of atoms in a 120 g sample of calcium Avogadro's number=6.022x 10^23 atoms in 1 mole
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3 years ago
If the formula for potassium chlorate is KClO3 and the formula for magnesium fluoride is MgF2, then what isthe formula for magne
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5 0
2 years ago
An ecosystem is a geographical area......
GrogVix [38]
The right answer for the question that is being asked and shown above is that: "where plants, animals, the landscape and the climate are all independent of each other." An ecosystem is a geographical area <span>where plants, animals, the landscape and the climate are all independent of each other.</span>
4 0
3 years ago
You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution when ex
mojhsa [17]

Answer:

a. 1.78x10⁻³ = Ka

2.75 = pKa

b. It is irrelevant.

Explanation:

a. The neutralization of a weak acid, HA, with a base can help to find Ka of the acid.

Equilibrium is:

HA ⇄ H⁺ + A⁻

And Ka is defined as:

Ka = [H⁺] [A⁻] / [HA]

The HA reacts with the base, XOH, thus:

HA + XOH → H₂O + A⁻ + X⁺

As you require 26.0mL of the base to consume all HA, if you add 13mL, the moles of HA will be the half of the initial moles and, the other half, will be A⁻

That means:

[HA] = [A⁻]

It is possible to obtain pKa from H-H equation (Equation used to find pH of a buffer), thus:

pH = pKa + log₁₀ [A⁻] / [HA]

Replacing:

2.75 = pKa + log₁₀ [A⁻] / [HA]

As [HA] = [A⁻]

2.75 = pKa + log₁₀ 1

<h3>2.75 = pKa</h3>

Knowing pKa = -log Ka

2.75 = -log Ka

10^-2.75 = Ka

<h3>1.78x10⁻³ = Ka</h3>

b. As you can see, the initial concentration of the acid was not necessary. The only thing you must know is that in the half of the titration, [HA] = [A⁻]. Thus, the initial concentration of the acid doesn't affect the initial calculation.

7 0
3 years ago
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