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3 years ago

A 2.2 M solution is made by with 0.45 moles of a solute. What is the final volume of this solution?

Chemistry

1 answer:

Savatey [412]3 years ago

7 0

Answer: The final volume of this solution is 0.204 L.

Explanation:

Given: Molarity of solution = 2.2 M

Moles of solute = 0.45 mol

Molarity is the number of moles of solute present divided by volume in liters.

$Molarity = \frac{no. of moles}{Volume (in L)}$

Substitute the values into above formula as follows.

$Molarity = \frac{no. of moles}{Volume (in L)}\\2.2 M = \frac{0.45}{Volume}\\Volume = 0.204 L$

Thus, we can conclude that the final volume of this solution is 0.204 L.

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$\begin{array}{lccccc}\text{R} & \text{HAc} & \leftrightharpoons & \text{H}^{+} & + & \text{Ac}^{-}\\\text{I} & 0.085 - 0.307 \; x& & 0 & & 0.307 \; x\\\end{array}$

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$\text{K}_{a} = [\text{H}^{+}] \cdot [\text{Ac}^{-}] / [\text{HAc}]\\\phantom{\text{K}_{a}} = 10^{-4.250} \times (10^{-4.250} + 0.307 \; x) / (0.085 - 10^{-4.250} - 0.307 \; x)$

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Thus it takes $0.0241 \; \text{L}$ of sodium hydroxide to produce this buffer solution.

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