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3 years ago

11

Alternate interior angels are____

1 answer:

Yuki888 [10]3 years ago

3 0

Congruent. In other words, the angle on the inside- if that makes sense

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Answer with solutions thank you

Eduardwww [97]

Answer:

${ \tt{ \frac{8}{ {b}^{2} - 4} . \frac{b - 2}{2b + 4} \div \frac{4}{2 {(b + 2)}^{2} } }} \\ \\ = { \tt{ \frac{8}{(b - 2)(b + 2)} \times \frac{b - 2}{2b + 4} \div \frac{4}{2 {(b + 2)}^{2} } }} \\ \\ = { \tt{ \frac{8}{b + 2} \times \frac{1}{2b + 4} \times \frac{2(b + 2) {}^{2} }{4} }} \\ \\ = { \tt{ \frac{8}{2b + 4} \times \frac{2b + 4}{4} }} \\ \\ = { \tt{ \frac{8}{4} }} \\ \\ = { \underline{ \tt{ \: 2 \: }}}$

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3 years ago

Find AB if BC = 4, BD = 5, and AD = 4.

snow_tiger [21]

The answer here is 6.40 and if oudd like it in square root just search the decimal in sqaure root

4 0

3 years ago

Someone please finish and explain this! i'm giving brainliest, tysm :)

posledela

Answer:

Step-by-step explanation:

Hours: 1 5 10 15 20 25

Minutes: 60 300 600 900 1,200 1,500

These show proportional relationship because they are all times hour by 60 minutes and the hours go by 5 hours, each.

6 0

3 years ago

If A ⊂ B, then<br><br> 1. A ∩ B = B<br> 2. A ∪ B = B<br> 3. A ∩ B = ∅

Alex

The answer is number 2

4 0

3 years ago

Read 2 more answers

Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .10 significa

nata0808 [166]

Answer:

The test statistics is $t = -1.40$

The critical value is $Z_{\alpha } = 2.33$

The null hypothesis is rejected

Step-by-step explanation:

From the question we are told that

The sample size for men is $n_1 = 80$

The sample proportion of men that own a cat is $\r p _M = 0.40$

The sample size for women is $n_2 = 80$

The sample proportion of women that own a cat is $\r p_F = 0.51$

The level of significance is $\alpha = 0.10$

The null hypothesis is $H_o : \r p _M = \ r P_F$

The alternative hypothesis is $H_a : \r p _M < \r p_F$

Generally the test statistic is mathematically represented as

$t = \frac{(\r p_M - \r p_F)}{\sqrt{\frac{(p_M*(1-p_M)}{n_1 } } + \frac{p_F*(1-pF)}{n_2 } }$

=> $t = \frac{(0.40 - 0.51)}{\sqrt{\frac{(0.40 *(1-0.41)}{80} } + \frac{0.51*(1-0.51)}{80 } }$

=> $t = -1.40$

The critical value of $\alpha$ from the normal distribution table is

$Z_{\alpha } = 2.33$

The p-value is obtained from the z-table ,the value is

$p-value = P( Z < -1.40) = 0.080757$

=> $p-value = 0.080757$

Given that the $p-value < \alpha$ then we reject the null hypothesis

7 0

3 years ago