Question

A manufacture inspects 800 light bulbs and finds that 796 of them have no defects. What is the experimental probability that a light build chosen at random has no defects

Answer 1

Answer:

The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.

Step-by-step explanation:

let S be the sample space for the inspection of the light bulbs.

Therefore, n(s) = 800

let ' A ' be the event of no defects bulbs.

Therefore, n(A) = 796

Now the Experiment probability for a light bulb chosen has no defects will be given by,

$P(A)=\dfrac{n(A)}{n(S)}$

Substituting the values we get

$P(A)=\dfrac{796}{800}=0.995$

The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.