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Veronika [31]
3 years ago
7

If a number is a multiple of 64, then it is a multiple of 8.

Mathematics
2 answers:
liq [111]3 years ago
3 0
Yes, that is correct but what is your question???
IgorC [24]3 years ago
3 0

a. If a number is a multiple of 64, then it is a multiple of 2.

b. The number is a multiple of 2.

c. The number is a multiple of 8.

d. If a number is not a multiple of 2, then the number is not a multiple of 64.

these are the answer to the question, you just got to know which one is correct?!

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5 and 13 GCF=? LCM=?
Gwar [14]

Answer:

G.C.F of 5 and 13 is 1.

L.C.M of 5 and 13 is 65.

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The quotient of three times a number and 8 is no more than 13
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Answer:

3n/8 ≤ 13

Step-by-step explanation:

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What is the binary number for 3​
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6 0
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Read 2 more answers
The 42 students who play wind instruments represent 75% of the students who are in band. How many students are in band?​
LUCKY_DIMON [66]

Answer:

56 students are in band

Step-by-step explanation:

Since 75% is basically 3/4, you should find first how much people are in 1/4 or 25%.

You can do this by dividing 42 and 3

42 divided by 3 = 14

You can check your answer because there are 42 students who play wind instruments and 14 + 14 + 14 = 42

Then you add another 14 to 42 since the students who play wind instruments are only 75%

42 + 14 = 56

56 students are in band

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csf%20%20%5Clarge%20%5C%3A%20find%20%5C%3A%20%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%20%20%5C%3A
solong [7]

<u>Given </u><u>:</u>

<u>\:  \:  \:</u>

  • \rm \large \: x = a ( \Theta + Sin  \Theta )

<u>\:  \:  \:</u>

  • \rm \large y = a ( 1 - cos   \: \Theta )

\:  \:

<u>Now , x = a ( θ + sin θ )</u>

<u>\:  \:</u>

<h3><u>Diff </u><u>w.</u><u>r</u><u>.</u><u>t</u><u> </u><u>"</u><u> </u><u>θ</u><u> </u><u>"</u></h3>

<u> </u>

<u>\:  \:  \:</u>

  • <u>\rm \large\frac{dx}{dθ }  = a \:  \frac{d}{dθ} (θ  +   \sin\theta )</u>

<u>\:  \:</u>

  • <u>\boxed{ \rm \large\underline{  \frac{dx}{d \theta} = a(1 +  \cos \theta )  }}</u>

<u>\:  \:</u>

<u>Now </u><u>y </u><u>=</u><u> </u><u>a </u><u>(</u><u> </u><u>1</u><u>-</u><u>c</u><u>o</u><u>s</u><u>θ</u><u>)</u>

<u>\:  \:</u>

<u>Diff </u><u>w.</u><u>r</u><u>.</u><u>t</u><u> </u><u>"</u><u> </u><u>θ</u><u> </u><u>"</u><u> </u><u>we </u><u>get </u><u>.</u>

<u>\:  \:</u>

  • <u>\rm \large   \frac{dy}{d \theta} = a \frac{d}{d \theta} (1 - cos \theta)</u>

<u>\:  \:  \:</u>

  • <u>\boxed{ \rm \large \underline{   \frac{dy}{d \theta} = a   \sin \theta}}</u>

<u>\:  \:  \:</u>

<u>From</u><u> </u><u>eqn </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>&</u><u> </u><u>(</u><u> </u><u>2</u><u> </u><u>)</u>

<u>\:  \:</u>

  • <u>\rm \large  \frac{dy}{dx}  =   \frac{ \frac{dy}{d \theta} }{\frac{dx}{d \theta}}</u>

<u>\:  \:  \:</u>

  • <u>\:  \:  \:  \rm \large =  \frac{ \cancel{a} \: sin \theta}{ \cancel a \: (1 + cos \theta)}</u>

<u>\:  \:</u>

  • <u>\rm \large \:  =  \frac{sin \theta}{1 +  \cos \theta }</u>

<u>\:  \:  \:</u>

  • <u>\rm \large \:  \frac{2 \sin( \frac{\theta }{2} ) cos\frac{\theta }{2} }{2 \: cos ^{2} \frac{\theta }{2}} \:  \:  ......(sin \: a \:  = 2 \: sin \frac{a}{2} \: cos \frac{a}{2} 1 +  \: cos \: a \:  = 2cos ^{2}  \frac{a}{2} )</u>

<u>\:  \:</u>

  • <u>\rm \large \:  \frac{dy}{dx}  =   \frac{sin \frac{ \theta}{2} }{cos  \frac{ \theta}{2} }</u>

<u>\:  \:</u>

  • <u>\rm \large \:  \frac{dy}{dx}  = tan \frac{ \theta}{2}</u>

<u>\:  \:</u>

  • <u>\rm \large \: ( \frac{dy}{dx}  )  = tan \frac{ \frac{ \theta}{2} }{2}</u>

<u>\:  \:</u>

  • <u>\rm \large \:  = tan( \frac{ \theta}{4} )</u>

<u>\:  \:</u>

  • <u>\boxed{ \rm \large \underline{ ( \frac{dy}{dx} ) =  \frac{\pi}{2}  = 1}}</u>

<u>\:  \:</u>

Hope Helps!:)

4 0
2 years ago
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