I cant figure the answer but its (-5,3)+3, and(5,3) + 4
Answer:
(1) x=
−1
/2
y+
5
/2
(2)
x=
−1
/2
y−2
Step-by-step explanation:
<u>(1)</u> 2x+y=5
Step 1: Add -y to both sides.
2x+y+−y=5+−y
2x=−y+5
Step 2: Divide both sides by 2.
2x
/2
=
(−y+5)/2
x=
−1
/2
y+
5
/2
<u>(2) </u>Step 1: Flip the equation.
−2x−4=y
Step 2: Add 4 to both sides.
−2x−4+4=y+4
−2x=y+4
Step 3: Divide both sides by -2.
−2x
/−2
=
(y+4)
/−2
x=
−1
/2
y−2
Answer:
x (7 y + 2 t )
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
Line pases through (6, 0) and (0, -6)
Slope = (0 - (-6))/(6 - 0) = 6/6 = 1
so y = 1*(x - 6) = x - 6
or x - y = 6
or 4x - 4y = 24
That is C
Answer:
a. The null hypothesis for this test is that the observed distribution is the same as uniform distribution
b. The degrees of freedom do you have for this test is 4
c. The calculated value of the test statistic is 9.250
Step-by-step explanation:
a. According to the given data we can conclude that the null hypothesis for this test is that the observed distribution is the same as uniform distribution.
b. In order to calculate the degrees of freedom do you have for this test we would have to make the following calculation:
degrees of freedom=k-1
degrees of freedom=5-1
degrees of freedom=4
c. In order to calculate the value of the test statistic first we have to calculate the frecuency expected as follows:
expected frecuency=total observed frecuency/total number of category
expected frecuency=1,000/5
expected frecuency=200
Hence, to calculate the value of the test statistic we have to calculate the following formula:
x∧2=∑(fo-fe)∧2/fe
=(185-200)∧2/200+(230-200)∧2/200+(215-200)∧2/200+(180-200)∧2+(190-200)∧2
=9.250
The calculated value of the test statistic is 9.250
