Ask question

Ask question

All categories

4 years ago

9

The Smiths own a home whose market value is $105,000. Their municipality taxes at 85% and the rate is 70 mills or $70 per thousa

nd. What will the Smiths pay in taxes?

2 answers:

barxatty [35]4 years ago

7 0

Answer: 6247.5

Step-by-step explanation:

85% x 105000 = 89250

70 x 89.25 = 6247.5

Allisa [31]4 years ago

3 0

Answer:

6247.50

Step-by-step explanation:

odyssey ware

You might be interested in

6. <br> omg someone please help w the correct answer

Neporo4naja [7]

This occurs for the input(s) x where the outputs, f(x) and g(x), are equal. So here, f(x) = g(x) when x = 1, because 5 = 5.

4 0

4 years ago

Quickly compute the following differences of squares. (a). 64^2 − 14^2 (b). 112^2 − 88^2 (c). 785^2 − 215^2

VikaD [51]

Answer:

(a) 3900

(b) 4800

(c) 570000

Step-by-step explanation:

We have given

(a) $64^2-14^2$

We know the algebraic equation $a^2-b^2=(a+b)(a-b)$

So $64^2-14^2=(64+14)(64-14)=3900$

(b) We know the algebraic equation $a^2-b^2=(a+b)(a-b)$

$112^-88^2=(112+88)(112-88)=4800$

(c) We know the algebraic equation $a^2-b^2=(a+b)(a-b)$

$785^2-215^2=(785+215)(785-215)=570000$

5 0

3 years ago

A maker of a certain brand of low-fat cereal barsclaims that the average saturated fat content is 0.5gram. In a random sample of

finlep [7]

Answer:

$t=\frac{0.475-0.5}{\frac{0.183}{\sqrt{8}}}=-0.386$

$p_v =2*P(t_{(7)}$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is different from 0.5 at 5% of signficance. So then the claim makes sense

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=0.475$

The sample deviation calculated $s=0.183$

We need to conduct a hypothesis in order to check if the true mean is 0.5 or no, the system of hypothesis would be:

Null hypothesis: $\mu = 0.5$

Alternative hypothesis: $\mu \neq 0.5$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{0.475-0.5}{\frac{0.183}{\sqrt{8}}}=-0.386$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=8-1=7$

Since is a two sided test the p value would be:

$p_v =2*P(t_{(7)}$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is different from 0.5 at 5% of signficance. So then the claim makes sense

4 0

3 years ago

Read 2 more answers

A chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The prem

katrin [286]

Amount of water = 260 gallons

Amount of antifreeze = 60 gallons

Explanation:

let the amount of water = w

amount of water + amount of antifreeze will give 320 gallons of mixture

w + amount of antifreeze = 320

amount of antifreeze = 320 - w ...(1)

The concentration for the antifreeze = 80% = 0.8

The concentration of the mixture = 15% = 0.15

From our question, we are mixing antifreeze with pure water (two different things). In our calculation, we can write the concentration in terms of water or in terms of antifreeze.

Writing the concentration in terms of amount of antifreeze

0.8(amount of antifreeze) + percent of antifreeze (amount of water) = concentraton of the mixture

The mixture contains 15% antifreeze

water contains no antifreeze, percent = 0

0.8(320 - w) + 0(w) = 0.15(amount of mixture)

0.8(320 - w) + 0 = 0.15(320)

256 - 0.8w + 0 = 48

256 - 0.8w = 48

collect like terms:

256 - 48 = 0.8w

208 = 0.8w

divide both sides by 0.8:

208/0.8 = w

w = 260

substitute for w in equation (1)

amount of antifreeze = 320 - 260 = 60

Amount of water = 260 gallons

Amount of antifreeze = 60 gallons

3 0

1 year ago

What proportion can be used to find 65% of 90

denpristay [2]

C because that’s the equations to find the proportion;)

8 0

4 years ago