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vfiekz [6]
4 years ago
11

Chlorine (Cl) forms a salt when it is combined with a metal. This element belongs in _____.

Chemistry
1 answer:
ella [17]4 years ago
8 0

Chlorine (Cl) forms a salt when it is combined with a metal. This element belongs in halogens. GROUP 17


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Find the de Broglie wavelength lambda for an electron moving at a speed of 1.00 \times 10^6 \; {\rm m/s}. (Note that this speed
masya89 [10]

(A) 7.28\cdot 10^{-10} m

The De Broglie wavelength of an electron is given by

\lambda=\frac{h}{p} (1)

where

h is the Planck constant

p is the momentum of the electron

The electron in this problem has a speed of

v=1.00\cdot 10^6 m/s

and its mass is

m=9.11\cdot 10^{-31} kg

So, its momentum is

p=mv=(9.11\cdot 10^{-31} kg)(1.00\cdot 10^6 m/s)=9.11\cdot 10^{-25}kg m/s

And substituting into (1), we find its De Broglie wavelength

\lambda=\frac{6.63\cdot 10^{-34}Js}{9.11\cdot 10^{-25} kg m/s}=7.28\cdot 10^{-10} m

(B) 1.16\cdot 10^{-34}m

In this case we have:

m = 0.143 kg is the mass of the ball

v = 40.0 m/s is the speed of the ball

So, the momentum of the ball is

p=mv=(0.143 kg)(40.0 m/s)=5.72 kg m/s

And so, the De Broglie wavelength of the ball is given by

\lambda=\frac{h}{p}=\frac{6.63\cdot 10^{-34} Js}{5.72 kg m/s}=1.16\cdot 10^{-34}m

(C) 9.02\cdot 10^{-9}m

The location of the first intensity minima is given by

y=\frac{L\lambda}{a}

where in this case we have

y=0.492 cm = 4.92\cdot 10^{-3} m

L = 1.091 is the distance between the detector and the slit

a=2.00\mu m=2.00\cdot 10^{-6}m is the width of the slit

Solving the formula for \lambda, we find the wavelength of the electrons in the beam:

\lambda=\frac{ya}{L}=\frac{(4.92\cdot 10^{-3}m)(2.00\cdot 10^{-6} m)}{1.091 m}=9.02\cdot 10^{-9}m

(D) 7.35\cdot 10^{-26}kg m/s

The momentum of one of these electrons can be found by re-arranging the formula of the De Broglie wavelength:

p=\frac{h}{\lambda}

where here we have

\lambda=9.02\cdot 10^{-9}m is the wavelength

Substituting into the formula, we find

p=\frac{6.63\cdot 10^{-34}Js}{9.02\cdot 10^{-9}m}=7.35\cdot 10^{-26}kg m/s

7 0
3 years ago
Select all that are true regarding stereoisomers,constitutional isomers, and conformational isomers
Tamiku [17]

Answer:To convert the model of one constitutional isomer to another constitutional isomer one needs to exchange 2 atoms/groups on different atoms.

To convert the model of one stereoisomer to another stereoisomer one needs to exchange 2 atoms/groups bonded to the same carbon.

To convert the model of one conformational isomer to another conformational isomer one only needs to rotate about single bond(s).

Explanation:

Constitutional isomers differ from each other in position of substituents. Hence if we interchange atoms or groups on two different atoms, we get constitutional isomers.

Stereo isomers posses different orientations in space. If two atoms or groups on the same carbon atoms interchange their spatial orientation, we have a different stereoisomer other than the original structure.

Conformers arise by free rotation across single bonds. Different conformers can be created by rotating single bonds.

8 0
3 years ago
Through electrolysis, a student collects 6.6 g of hydrogen gas and 52.4 g of oxygen gas. The reaction was allowed to proceed to
Kaylis [27]

Answer: 59 grams

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

2H_2O\rightarrow 2H_2+O_2

Given: mass of hydrogen = 6.6 g

mass of oxygen = 52.4 g

Mass of products = Mass of hydrogen + mass of oxygen = 6.6 +52.4 = 59 g grams

Thus mass or reactant = mass of water

Mass of reactants = mass of products = 59 g

Thus the mass of water initially present was 59 g.

3 0
4 years ago
How many moles of Si are in 78.0 grams of silicon
gladu [14]
The answer is 2.78 moles of Si

6 0
3 years ago
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The rapid movement of gases molecules can be explained because gases have ___ size particles and exert _____ attraction for othe
Marrrta [24]
The answers that fit the blanks are SMALL and LITTLE, respectively. The particles or molecules or fas are small which makes it loose and easily moves around, and these only exert little attraction for other gas particles. The answer for this would be option D.
5 0
3 years ago
Read 2 more answers
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