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Nady [450]
2 years ago
15

What volume of water has the same mass as 3.0m3 of ethyl alcohol?

Chemistry
1 answer:
erastovalidia [21]2 years ago
5 0
<span>The first thing a person has to do is determine how much volume of water ethyl alcohol contains. You do this by burning the liquid and the volume that sits at the bottom is water. You take this and then determine how much 3.0m3 has and that answer is 2.0ml.</span>
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Distinguish between zinc nitrate and lead nitrate ​
Kobotan [32]

Answer:

Zinc nitrate gives white ppt. which dissolves in excess ammonium hydroxide and produce a colorless solution whereas lead nitrate gives a chalky white ppt. of lead hydroxide which doesnot dissolve.

Explanation:

Hope this helps :)

7 0
3 years ago
¿Cuál de las siguientes configuraciones globales corresponde a un elemento químico que se comporta como metal? 1 punto [He]2s2 2
yuradex [85]

Answer:

[Ne]3s2

Explanation:

ahora tenemos que mirar cada una de las configuraciones electrónicas de cada átomo de cerca antes de tomar una decisión.

considerando la configuración electrónica más externa de cada una de las especies mostradas;

para la primera configuración, ns2 np6 corresponde a un gas noble.

para la segunda configuración ns2 np3 corresponde a un elemento no metálico del grupo 5.

para la tercera configuración, ns2 corresponde a un elemento metálico del grupo 2.

para la cuarta configuración, ns2 np4 corresponde a un elemento no metálico del grupo 6

5 0
3 years ago
The density of copper is 8.68 g/mL use the density value to determine how many moles are
statuscvo [17]

Answer:

17.1 mol

Explanation:

(8.68g/mL * 125 mL) = 1085 g

1085 g/ (63.55 g/mol) = 17.1 mol

5 0
2 years ago
The standard internal energy change for a reaction can be symbolized as Δ U ∘ rxn or Δ E ∘ rxn . For each reaction equation, cal
rosijanka [135]

Answer : The internal energy change is, -506.3 kJ/mol

Explanation :

Formula used :

\Delta H=\Delta U+\Delta n_gRT

or,

\Delta U=\Delta H-\Delta n_gRT

where,

\Delta H = change in enthalpy = -511.3kJ/mol=-511300.0J/mol

\Delta U = change in internal energy = ?

\Delta n_g = change in moles

Change in moles = Number of moles of product side - Number of moles of reactant side

According to the reaction:

Change in moles = 0 - 2 = -2 mole

That means, value of \Delta n_gRT = 0

R = gas constant = 8.314 J/mol.K

T = temperature = 25^oC=273+25=298K

Now put all the given values in the above formula, we get

\Delta U=\Delta H-\Delta n_gRT

\Delta U=(-511300.0J/mol)-[-2mol\times 8.314J/mol.K\times 298K

\Delta U=-511300.0J/mol+4955.144J/mol

\Delta U=-506344.856J/mol=-506.3kJ/mol

Therefore, the internal energy change is -506.3 kJ/mol

6 0
3 years ago
How many liters of O2 gas will be produced at STP from 4 moles of KC1O3
quester [9]

Answer:

V = 134.5 L

Explanation:

Given data:

Number of moles of KClO₃ = 4 mol

Litters of oxygen produced at STP = ?

Solution:

Chemical equation:

2KClO₃  →  2KCl   + 3O₂

Now we will compare the moles of KClO₃ with oxygen.

                    KClO₃        :           O₂

                        2            :           3

                        4            ;          3/2×4 = 6 mol

Litters of oxygen at STP:

PV = nRT

V = nRT/P

V = 6 mol × 0.0821 atm.L/mol.K × 273 K / 1atm

V = 134.5 L / 1

V = 134.5 L

5 0
3 years ago
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