Answer:
1, 2, and 3 are true.
Explanation:
The Henderson-Hasselbalch equation is:
pH = pka + log₁₀ ![\frac{[A^-]}{[HA]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D)
- If the pH of the solution is known as is the pKa for the acid, the ratio of conjugate base to acid can be determined. <em>TRUE</em>
pH = pka + log₁₀
If you know pH and pka:
10^(pH-pka) =
The ratio will be: 10^(pH-pka)
- At pH = pKa for an acid, [conjugate base] = [acid] in solution. <em>TRUE</em>
pH = pka + log₁₀
0 = log₁₀
10^0 =
1 =
As ratio is 1, [conjugate base] = [acid] in solution.
- At pH >> pKa for an acid, the acid will be mostly ionized. <em>TRUE</em>
pH = pka + log₁₀
If pH >> pKa, 10^(pH-pka) will be >> 1, that means that you have more [A⁻] than [HA]
- At pH << pKa for an acid, the acid will be mostly ionized. <em>FALSE</em>
pH = pka + log₁₀
If pH << pKa, 10^(pH-pka) will be << 1, that means that you have more [HA] than [A⁻]
I hope it helps!
Answer:
The answer to your question is below
Explanation:
There are 4 types of chemical reactions:
- Synthesis is when two elements or compounds form only one compound.
- Decomposition is when 1 compound is broken into 2 or more products.
- Single replacement is when one element is replaced by another element.
- Double replacement is when the cations of two compounds are interchanged.
6.- Synthesis Al + 3Cl ⇒ AlCl₃
7.- Double replacement 2NaOH + H₂SO₄ ⇒ Na₂SO₄ + 2H₂O
8.- Decomposition Ni(ClO₃)₂ ⇒ NiCl₂ + 3O₂
9.- Combustion 2C₄H₁₀ + 13O₂ ⇒ 8CO₂ + 10H₂O
10.- Single replacement Zn + 2HCl ⇒ ZnCl₂ + H₂
Answer:
Q,N,1) lithium + hydrochloric -> lithium chloride + Hydrogen.
- word equation ( 2li + 2HCl -> 2liCl + H2)
Explanation:
The reaction equation will be as follows.
It is given that the total energy liberated is -2810 kJ/mol. As the sign is negative this means that energy is being released. Also, it is given that the energy required to synthesis is -64.1 kJ/mol.
Therefore, calculate the number of moles of compound as follows.
No. of moles = 
= 
= 43.83 mol
= 44 mol (approx)
Thus, we can conclude that the number of moles of compound is 44 mol.
Agreed with the person on top ^^^
