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Ann [662]
3 years ago
15

The answer choices are in the photo

Mathematics
2 answers:
kirill [66]3 years ago
5 0

Answer:

35 units²

Step-by-step explanation:

The area (A) of a triangle is calculated as

A = \frac{1}{2} bh ( b is the base and h the perpendicular height )

Here b = 14 and h = 5, thus

A = \frac{1}{2} × 14 × 5 = 7 × 5 = 35 units²

Marta_Voda [28]3 years ago
5 0
35units lololololololololololololololoo
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What is the least common multiple of 45, 3, and 5
SIZIF [17.4K]

Answer:

45

Step-by-step explanation:

3 and 5 both go into 45 and 45 is the smallest for it

8 0
3 years ago
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For a polynomial p(x), the value of p(3) is −2. Which of the following must be true about p(x)?
mr Goodwill [35]

Answer:

D

Step-by-step explanation:

The factor theorem states if (x - h) is a factor of a polynomial p(x) then

p(h) = 0

However, p(h) ≠ 0 then the value obtained is the remainder.

Thus

p(3) = - 2

When p(x) is divided by (x - 3) then the remainder is - 2

8 0
3 years ago
What is the length of in the rectangular prism? Round to the nearest tenth of a centimeter. A.
BaLLatris [955]
Can you explane it a little more.
7 0
3 years ago
The green triangle is a dilation of the red triangle with a scale factor of s=13 and the center of dilation is at the point (4,2
maxonik [38]

Given:

The red figure dilated with a scale factor of s=\dfrac{1}{3} and the center of dilation is at the point (4,2) to get the green figure.

To find:

The coordinates of C' and A.

Solution:

If a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

In given problem, the scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Let the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Therefore, the coordinates of Point C' are C'(2,5).

We assumed that point A is A(m,n).

Using (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

\dfrac{1}{3}(m-4)=8-4

(m-4)=3(4)

m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

4 0
3 years ago
Use angle relationships to complete the top equation. Then, solve for x and find the measure of both angles.
likoan [24]
4x + 80 = 180
x = 25

2x + 80 = 130
2x = 50
7 0
2 years ago
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