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3 years ago

Write each percent as a fraction 10. 56 564%

2 answers:

5 0

10.56 as a fraction is 10 14/25 because you keep the whole number which is 10 and then put 56/100 ( it is a hundredth) and simplify it to make it 14/25 so, our answer is 10 wholes and 14 over 25.

564% as a fraction is 5 16/25 because you put 564 over 100 and simplify so, 564/100 = 5 wholes and 16 over 25.

torisob [31]3 years ago

3 0

10.56 as a fraction is 264 / 25
564% as a fraction is 141/250

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SOMEONE HELP! PLEASE! read the attached files

Trava [24]

Answer: 43 squared units

Explanation:

So the area is the total amount of the inside of the polygon (I’m not good at explaining) and you get your area from using measurements on the sides of the shape for example for a square let’s say the side is 4 and another side is 4 so you multiply that and you get 16 which is the area

So basically since this one is a open polygon you can just count the inside of the poly using the squares

7 0

3 years ago

Solve the system by substitution.<br> y = -3x + 4<br> y = -7x<br> Submit Answer

iVinArrow [24]

Answer:

{y,x} = {7,-1}

Step-by-step explanation:

(-7x) + 3x = 4

- 4x = 4

4x = - 4

x = - 1

y = -7x

x = -1

y = -7(-1) = 7

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3 years ago

A student believes she can earn between $5200 and $6250 from her summer job. She knows that she will have to buy four new tires

ohaa [14]

Answer:

4180 to 5230$

Step-by-step explanation:

1. Lets find the expenses she has to make -> 4*90+660=1020$(4 new tires + other expenses)

2. As her income is not set strictly we can guess the range she can save(More accurate calculations depends on her strict incomes). We have 5200-1020=4180$(if she gets paid 5200$) and 6250-1020= 5230$(if she gets paid 6250$).

3. So the range of savings vary from 4180 to 5230$$.

4 0

3 years ago

53 dL = ______ daL im struggling with this one<br> .

sladkih [1.3K]

Answer:

0.53 daL

Step-by-step explanation:

4 0

3 years ago

Which two values of x are roots

FrozenT [24]

The answer is C.

To solve these types of equations you first need to make sure that you equation is equal to 0. In this case all of the numbers are already on the same side so no work needs to be done there. Then we can get a, b and c values for the quadratic equation by looking at the coefficients.

a = 4 (number attached to x^2)
b = -6 (number attached to x)
c = 1 (number with no variable attached)

Now we can put this into the quadratic equation.

$\frac{-b +/- \sqrt{ b^{2} -4ac} }{2a}$

$\frac{6 +/- \sqrt{ -6^{2} -4(4)(1)} }{2(4)}$

$\frac{6 +/- \sqrt{20} }{8}$

6 0

4 years ago