Question

I REALLY NEED HELP !!! HOW DO YOU DO THIS?

Answer 1

Answer:

Step-by-step explanation:

a. AB pass thro' (0,3) n (5,0)

so its eqn is (y-3)/(x-0) = (3-0)/(0-5)=-3/5

y=(-3/5)x + 3

b. area of ABC=1/2*base*height

=1/2*3*5=7.5

c. line perpendicular to AB has slope = 1/slope of line AB

= 1/(-3/5)

= -5/3

it passes thro' A (0,3) which is the y-intercept

so its eqn is y = (-5/3)x + 3