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iragen [17]
3 years ago
8

A drill can dig through rock at a rate of 2 1/2 inches per hour. How many hours will it take for the drill to reach five feet be

low the rocky surface, assuming it maintains this rate of digging?
Mathematics
2 answers:
anygoal [31]3 years ago
8 0

Answer:  24 hours

Step-by-step explanation:

Given : A drill can dig through rock at a rate of 2\dfrac{1}{2} inches per hour.

i.e. Speed=  2\dfrac{1}{2}=\dfrac{5}{2} inches per hour.

Formula we use here is : \text{Time}=\dfrac{\text{Depth}}{\text{Speed}}

We assume that it maintains this rate of digging.

Since 1 feet = 12 inches

Depth to dig = 5\ \text{feet}=5\times12=60\text{ inches}

The number of hours it will take  for the drill to reach 5 feet below the rocky surface will be

\text{Time}=\dfrac{60}{\dfrac{5}{2}}=\dfrac{60\times2}{5}=24

Hence, it will take 24 hours for the drill to reach five feet below the rocky surface.

Gre4nikov [31]3 years ago
7 0
5 feet is equal to 60 inches. 60 inches divided by 2.5 inches per hour means it would take 24 hours for the drill to reach five feet (assuming it maintains the same rate of digging)
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Step-by-step explanation:

5 - 14 = -9

-9 + 0 = -9

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3 years ago
A)180.48 m2<br><br> B)180.48 m<br><br> C)80.48 m2<br><br> D)80.48 m
MissTica

Answer:

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Step-by-step explanation:

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4 0
2 years ago
AAA Packages Plus sends packages overnight for $5 plus $0.25 per ounce. United Packages charges $2 plus $0.35 per ounce.
Nata [24]
A.)
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7 0
2 years ago
Need help ASAP please
OlgaM077 [116]

Step-by-step explanation:

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6 0
2 years ago
The model represents x2 – 9x + 14. An algebra tile configuration showing only the Product spot. 24 tiles are in the Product spot
klio [65]

I didn't get all the part with the tiles, but here's the general answer:

given a polynomial

p(x)=ax^2+bx+c

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p(k)=ak^2+bk+c=0

So, given the polynomial

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We can check if x-9 is a factor by evaluating p(9):

p(9)=81-81+14=14\neq 0

So, x-9 is not a factor.

Similarly, we can evaluate p(2),\ p(-5),\ p(-7) to check if x-2,\ x+5,\ x+7 are factors:

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4 0
3 years ago
Read 2 more answers
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