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Dima020 [189]
3 years ago
14

What is the prime factorization of 80? A.2×2×2×5 B.2×2×3×5 C.2×2×2×3×5 D.2×2×2×2×5

Mathematics
2 answers:
Serggg [28]3 years ago
6 0

2*2*2*2*5 = 8, so the answer is...

D).

Nonamiya [84]3 years ago
3 0

The answer would be (d.) , it can also be put as 2^4*5

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Answer:

47+47+90+90= 274, 360-274= 86, 86÷2=43=x

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Do we go back 2 ppaces or go forward 2 places when making percenta into decimals
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Move the decimal to the left 2 spaces.  90% would .90.  74% would be .74.  134% would be 1.34  Got it?  It' always the same no matter the percent.  2 spaces to the left.
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There are 10 multiple choice questions in an examination. first 4 have 5 choices each and remaining have 4 choices each. how man
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2560000 sequences of answers are possible.

<em><u>Explanation</u></em>

Total number of questions = 10

First 4 questions have 5 choices each and remaining (10-4)= 6 questions have 4 choices each.

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and the possible sequences of answers for remaining 6 questions = 4^6=4096

Thus, the total possible number of sequences of answers = (625 × 4096) = 2560000

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The product of two positive numbers is 1,800. One number is twice the other number. The equation to determine the two numbers, w
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A credit card company charges 18.6% percent per year interest. Compute the effective annual rate if they compound, (a) annualy,
Darina [25.2K]

Answer:

a) Effective annual rate: 18.6%

b) Effective annual rate: 20.27%

c) Effective annual rate: 20.43%

d) Effective annual rate: 20.44%

Step-by-step explanation:

The effective annual interest rate, if it is not compounded continuously, is given by the formula

I=C(1+\frac{r}{n})^{nt}-C

where

<em>C = Amount of the credit granted </em>

<em>r = nominal interest per year </em>

<em>n = compounding frequency </em>

<em>t = the length of time the interest is applied. In this case, 1 year. </em>

In the special case the interest rate is compounded continuously, the interest is given by

I=Ce^{rt}-C

(a)  Annually

I=C(1+\frac{0.186}{1})-C=C(1.186)-C=C(1.186-1)=C(0.186)

The effective annual rate is 18.6%

(b) Monthly

<em>There are 12 months in a year </em>

I=C(1+\frac{0.186}{12})^{12}-C=C(1.2027)-C=C(0.2027)

The effective annual rate is 20.27%

(c) Daily

<em>There are 365 days in a year </em>

I=C(1+\frac{0.186}{365})^{365}-C=C(1.2043)-C=C(0.2043)

The effective annual rate is 20.43%

(d)  Continuously

I=Ce^{0.186}-C=C(1.2044)-C=C(0.2044)

The effective annual rate is 20.44%

3 0
3 years ago
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