Answer:
is the required simplification.
Step-by-step explanation:
Here, the given expression is (6x−4)(3x−1).
By DISTRIBUTIVE PROPERTY of numbers:
A ( B + C ) = AB + AC
Simplifying the given expression, we get:
or,
Hence the given expression is simplified.
Answer:
The probability that none of the 10 calls result in a reservation is 0.60%. In turn, the probability that at least one call results in a reservation being made is 99.40%.
Step-by-step explanation:
Since approximately 40% of the calls to an airline reservation phone line result in a reservation being made, supposing an operator handles 10 calls, to determine what is the probability that none of the 10 calls result in a reservation, and what is the probability that at least one call results in a reservation being made, the following calculations must be performed:
0.6 ^ 10 = X
0.006 = X
0.006 x 100 = 0.60%
Therefore, the probability that none of the 10 calls result in a reservation is 0.60%.
100 - 0.60 = 99.40
In turn, the probability that at least one call results in a reservation being made is 99.40%.
The statement that best describes the information about the medians would be: the class median and exam median are almost the same.
<h3>Median of a Data Set on a Box Plot</h3>
- The median of any data distribution that is plotted on a box plot is indicated by the vertical line that divides the rectangular box in the box plot.
Thus:
- The median for class is 84
- The median for exam is 85.
Therefore, the statement that best describes the information about the medians would be: the class median and exam median are almost the same.
Learn more about Box Plot on:
brainly.com/question/10209877
I'm confused because the answer is 220 quarts.
If you look at the other one you asked, I explained it.
Answer:
The answer is 2 1/6
Step-by-step explanation:
First you would divide 13 by six and that would leave you with 2 with a remainder of 1. Then you would put together the fraction leaving 6 as the denominator, 2 as the whole number, and 1 as the numerator.
Let me know if you need any other help!
