All categories

2 years ago

Josiah skateboards from his house to school 3 miles away. It takes him 36 minutes.

1 answer:

4 0

Using the speed - distance relationship, the number of minutes it will take Josiah to cover a distance of 2.5 miles is 30 minutes.

Calculating Josiah's speed :

Speed = (distance ÷ time)

Speed = (3 ÷ 36) = 0.08333 miles per minute.

Time taken to cover a distance of 2.5 miles :

Time taken = (Distance ÷ Speed)

Time taken = (2.5 ÷ 0.08333) = 30 minutes

Therefore, it will take 30 minutes for Josiah to cover a distance of 2.5 Miles

Learn more : brainly.com/question/18112348

You might be interested in

Find the value of x in the isosceles triangle shown below.

joja [24]

Answer: C. 10

Explanation:

Take half right triangle from the isosceles triangle:

We get side lengths:

12/2 = 6, 8, and x

And use Pythagorean’s theorem to find x:

6^2 + 8^2 = x^2
36 + 64 = x^2
100 = x^2
10 = x

7 0

2 years ago

Simplify √49 + [√81 - x(9x = 14)]

eimsori [14]

$\longrightarrow{\green{- 9 {x}^{2} + 14x + 16}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

$\sqrt{49} + [ \sqrt{81} - x \: (9x - 14) ] \\ \\ = \sqrt{7 \times 7} + [ \sqrt{9 \times 9} - 9 {x}^{2} + 14x] \\ \\ = \sqrt{( {7})^{2} } + [ \sqrt{ ({9})^{2} } - 9 {x}^{2} + 14x ] \\ \\ (∵ \sqrt{ ({x})^{2} } = x ) \\ \\ = 7 + (9 - 9 {x}^{2} + 14x) \\ \\ = 7 + 9 - 9 {x}^{2} + 14x \\ \\ = - 9 {x}^{2} + 14x + 16$

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}$

3 0

3 years ago

The diameter of a circle is 36 feet. What is the area?

Alex73 [517]

Answer:

18 feet

Step-by-step explanation:

3 0

3 years ago

The time a basketball player spends in the air when shooting a basket is called the "hang time." the vertical leap l measured i

Marina86 [1]

Dénote l the vertical leap, then the given equation can be written like this:
$l(t)=4t^2\\\text{Since one inch equate 0.0833333 feet then 44 inches equate }\\44\times 0.0833333=3.6feet\\\text{Add to 33 feet like this:}\\33+3.6=36.6feet\\\text{Now we have to solve the equation:}\\4t^2=36.6\\\text{Divide over 4 we get:}\\t^2= \frac{36.6}{4}=9.15\\\text{Take the square root we get:}\\t=\sqrt{9.15}=3$

The hang time equates then 3 seconds

7 0

3 years ago

Inveres laplace transform (3s-14)/s^2-4s+8

Olenka [21]

Complete the square in the denominator.

$s^2 - 4s + 8 = (s^2 - 4s + 4) + 4 = (s-2)^2 + 4$

Rewrite the given transform as

$\dfrac{3s-14}{s^2-4s+8} = \dfrac{3(s-2) - 8}{(s-2)^2+4} = 3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}$

Now take the inverse transform:

$L^{-1}_t\left\{3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3L^{-1}_t\left\{\dfrac{s-2}{(s-2)^2+2^2}\right\} - 4L^{-1}_t\left\{\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3e^{2t} L^{-1}_t\left\{\dfrac s{s^2+2^2}\right\} - 4e^{2t} L^{-1}_t\left\{\dfrac{2}{s^2+2^2}\right\} \\\\ \boxed{3e^{2t} \cos(2t) - 4e^{2t} \sin(2t)}$

5 0

2 years ago