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3 years ago

HELP 25 POINTS Calc multiple choice

Mathematics

2 answers:

alexgriva [62]3 years ago

8 0

Answer:

answer is B

Step-by-step explanation:

online sources

Zigmanuir [339]3 years ago

5 0

I think it’s d sorry if I’m wrong

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Complete the equation so that it has solutions of –5 and 7. x2 x = 0

Pavlova-9 [17]

The equation it has solutions of –5 and 7 is x^2-2x-37=0

We have equation

solutions of equation are –5 and 7.

We have to find complete the equation.

We have given that solutions of the equation are -5, 7.

The standard form of a quadratic equation.

<h3>What is the factor of the quadratic equation?</h3>

$(x -\alpha) (x- \beta)$

Where we have

$p = -(\alpha+\beta) and q = (\alpha\times \beta)$

So, roots are

$( x- (-5)) (x-7)$

$p = -( -5+7)$ , $q =(-5)(7).$

$p = -2 and q = -35.$

On substituting p and q in equation

$x^2+(-2)x-37=0$

$x^2-2x-37=0$

Therefore,x^2-2x-37=0 is the equation of solution -5,7.

To learn more about the quadratic factor visit:

brainly.com/question/472337

4 0

2 years ago

Read 2 more answers

Kate used 6.15 meters of ribbon to make bows. How many centimeters of ribbon did she use? 61.5 centimeters 0 0.615 centimeter 6.

saul85 [17]

Answer:

615 centimeters

Step-by-step explanation:

Kate used 6.15 meters of ribbon to make a bow

The centimeters of the ribbon used by kate can be calculated as follows

1 meter=100 centimeters

6.15 meters= x

Cross multiply both sides

1 × x = 6.15 × 100

x = 615 centimeters

Hence Kate used 615 centimeters of the ribbon

8 0

4 years ago

STEPHANIE OPENED HER BOOK AND FOUND THAT THE PRODUCT OF THE PAGE NUMBER FOR TWO FACING PAGES WAS 3,906. WHAT WERE THE PAGE NUMBE

viktelen [127]

63 and 62.

63*62 = 3906

6 0

3 years ago

Find the coefficient of the x^4y^2 term in the expansion of (2x+y)^6

Elina [12.6K]

Answer:

240

Step-by-step explanation:

When you factor it out, you get:

$64x^6 + 192x^5y +240x^4y^2 + 160x^3y^3 + 60x^2y^4 +12xy^5 + y^6$

8 0

3 years ago

Doing research for insurance rates, it is found that those aged 30 to 49 drive an average of 38.7 miles per day with a standard

Alja [10]

Answer: 0.4302

Step-by-step explanation:

Given : Mean : $\mu=\text{38.7 miles }$

Standard deviation : $\sigma=\text{6.7 miles }$

Sample size : $n=60$

Also, these distances are normally distributed.

Then , the formula to calculate the z-score is given by :-

$z=\dfrac{x-\mu}{\sigma}$

For x=32.5

$\\\\ z=\dfrac{32.5-38.7}{6.7}=-0.925373134\approx-0.93$

For x=40.5

$\\\\ z=\dfrac{40.5-38.7}{6.7}=0.268656\approx0.27$

The p-value = $P(-0.93$

$=P(0.27)-P(-0.93)=0.6064198- 0.1761855=0.4302343\approx0.4302$

Hence, the required probability :-0.4302

3 0

3 years ago