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bulgar [2K]
3 years ago
6

HELP 25 POINTS Calc multiple choice

Mathematics
2 answers:
alexgriva [62]3 years ago
8 0

Answer:

answer is B

Step-by-step explanation:

online sources

Zigmanuir [339]3 years ago
5 0
I think it’s d sorry if I’m wrong
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Help help help help help help help
earnstyle [38]

Answer:

The first one is 90, and the second one is 150

Explanation:

40% of 90 is 36, and

40% of 150 is 60.

8 0
3 years ago
Consider the functions f(x) = 12^x and g(x)= -2(12)^x. Which transformations must be applied to function F to produce the graph
maksim [4K]

Answer:

Step-by-step explanation:

g(x) = -2f(x)

Vertical stretch                       by virtue of the factor 2

Reflection over the x-axis      by virtue of the factor -1

5 0
2 years ago
I WILL GIVE BRAINIEST IF CORRECT <br> What is the equation of this graph?
slega [8]
It should be the 2nd or 4th answer, i’m not COMPLETELY sure. I’m positive it’s the 4th answer
7 0
3 years ago
Plzzzzz help right answer gets a brainly!
Ivenika [448]

Answer:

8

Step-by-step explanation:

16 divided by 8 equals 2 then 24 divided by 8 equals 3 Answer: 8

6 0
3 years ago
(c). It is well known that the rate of flow can be found by measuring the volume of blood that flows past a point in a given tim
aleksklad [387]

(i) Given that

V(R) = \displaystyle \int_0^R 2\pi K(R^2r-r^3) \, dr

when R = 0.30 cm and v = (0.30 - 3.33r²) cm/s (which additionally tells us to take K = 1), then

V(0.30) = \displaystyle \int_0^{0.30} 2\pi \left(0.30-3.33r^2\right)r \, dr \approx \boxed{0.0425}

and this is a volume so it must be reported with units of cm³.

In Mathematica, you can first define the velocity function with

v[r_] := 0.30 - 3.33r^2

and additionally define the volume function with

V[R_] := Integrate[2 Pi v[r] r, {r, 0, R}]

Then get the desired volume by running V[0.30].

(ii) In full, the volume function is

\displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

Compute the integral:

V(R) = \displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

V(R) = \displaystyle 2\pi K \int_0^R (R^2r-r^3) \, dr

V(R) = \displaystyle 2\pi K \left(\frac12 R^2r^2 - \frac14 r^4\right)\bigg_0^R

V(R) = \displaystyle 2\pi K \left(\frac{R^4}2- \frac{R^4}4\right)

V(R) = \displaystyle \boxed{\frac{\pi KR^4}2}

In M, redefine the velocity function as

v[r_] := k*(R^2 - r^2)

(you can't use capital K because it's reserved for a built-in function)

Then run

Integrate[2 Pi v[r] r, {r, 0, R}]

This may take a little longer to compute than expected because M tries to generate a result to cover all cases (it doesn't automatically know that R is a real number, for instance). You can make it run faster by including the Assumptions option, as with

Integrate[2 Pi v[r] r, {r, 0, R}, Assumptions -> R > 0]

which ensures that R is positive, and moreover a real number.

5 0
3 years ago
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