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bulgar [2K]
3 years ago
6

HELP 25 POINTS Calc multiple choice

Mathematics
2 answers:
alexgriva [62]3 years ago
8 0

Answer:

answer is B

Step-by-step explanation:

online sources

Zigmanuir [339]3 years ago
5 0
I think it’s d sorry if I’m wrong
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Please help I'm struggling so bad right now
Over [174]

Answer:

y = m x + b     is the standard form of a straight line

m = (y2 - y1) / (x2 - x1) = (10 - (-8)) / (-3 - 0) = 18 / -3 = -6

When x = 0 y = b from the equation for a line

y = - 8

So our equation is  

y = -6 x - 8

As a check let x = -2 then

y = (-6 * -2) - 8 = 12 - 8 = 4

Check on the graph to verify that this equation holds

8 0
2 years ago
Which value of b will cause the quadratic equation x^2+bx+5=0 to have two real number solution
Aloiza [94]
To have 2 real number solutions  the discriminant b^2 - 4ac  must be greater than zero.

so the condition  for 2 real roots in this equation is:-

b^2 - 4*1*5 > 0
b^2 >  20

b > sqrt 20    ( positive root)    Answer
5 0
3 years ago
Read 2 more answers
Finding values or<br> k(x) = x - 2<br> h(x) = x2 +1<br> (h + k)(2) =
Serjik [45]

Answer:

<h2>(h + k)(2) = 5</h2>

Step-by-step explanation:

(h+k)(x)=h(x)+k(x)\\\\\bold{METHOD\ 1:}\\\\k(x)=x-2,\ h(x)=x^2+1\\\\(k+h)(2)=h(2)+k(2)\\\\\text{Calculate}\ h(2)\ \text{and}\ k(2).\\\text{Put}\ x=2\ \text{to the equations of the functions}\\\\h(2)=2^2+1=4+1=5\\k(2)=2-2=0\\\\\text\\\\\text{Substitute:}\\\\(h+k)(2)=5+0=5

\bold{METHOD\ 2:}\\\\k(x)=x-2,\ h(x)=x^2+1\\\\(h+k)(x)=h(x)+k(x)=(x^2+1)+(x-2)=x^2+x-1\\\\(h+k)(2)-\text{put}\ x=2\\\\(h+k)(2)=2^2+2-1=4+2-1=6-1=5

5 0
2 years ago
Identify the slope and y−intercept of the line with the equation 18x − 6y = 12.
DaniilM [7]
And where is the graph? I'll change my answer.
5 0
3 years ago
How do you write x+y=9 in y=mx+b?
Alina [70]
Y=-x+9 is the correct answer
4 0
3 years ago
Read 2 more answers
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