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3 years ago

Determine the 10th term from the end of the AP 4, 9, 14

Mathematics

1 answer:

77julia77 [94]3 years ago

6 0

Answer:

<h2>The answer is 49</h2>

Step-by-step explanation:

Since the sequence above is an arithmetic sequence

For an nth term in an arithmetic sequence

A(n) = a + ( n - 1)d

where a is the first term

n is the number of terms

d is the common difference

To find the 10th term of the sequence first find the first term and the common difference

From the question

a = 4

d = 9 - 4 = 5 or 14 - 5 = 9

Since we are finding the 10th term

n = 10

Substitute the values into the above formula

That's

A(10) = 4 +(10-1)5

= 4 + 9(5)

= 4 + 45

We have the final answer as

Hope this helps you

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3 years ago

Multiply the additive inverse of (-7/8) by the reciprocal of (5 1/2)<br><br>PLEASE HELP!

EleoNora [17]

Answer:

$\bold {$\dfrac{7}{44}$}$

Step-by-step explanation:

<h3> Reciprocal:</h3>

$\sf \text{The reciprocal of any number $\dfrac{a}{b}$ is given by $\dfrac{b}{a}$}\\\\5\dfrac{1}{2}=\dfrac{11}{2}\\\\\text{Reciprocal of $\dfrac{11}{2}$ = $\dfrac{2}{11}$}$

<h3>Additive inverse:</h3>

$\text{Additive inverse of $\dfrac{-7}{8}$=$\dfrac{7}{8}$}$

Now multiply,

$\sf \dfrac{7}{8}*\dfrac{2}{11}=\dfrac{7}{4}*\dfrac{1}{11}\\$

$=\dfrac{7}{44}$

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2 years ago

What affect does "h" have on the parent function y = 1/x ?

pochemuha

If h moves the graph left or right, $y= \frac{1}{x+h}$ (moves left)
$y= \frac{1}{x-h}$ (moves right)

If a vertical stretch by a factor of |h|, then $y = \frac{h}{x}$

If h moves the graph up or down, $y= \frac{1}{x} +h$ (moves up)
$y= \frac{1}{x} -h$ (moves down)

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3 years ago

Problem<br> How many numbers between 111 and 100100100 (inclusive) are divisible by 101010 or 777?

olga2289 [7]

I suspect you meant

"How many numbers between 1 and 100 (inclusive) are divisible by 10 or 7?"

• Count the multiples of 10:

⌊100/10⌋ = ⌊10⌋ = 10

• Count the multiples of 7:

⌊100/7⌋ ≈ ⌊14.2857⌋ = 14

• Count the multiples of the LCM of 7 and 10. These numbers are coprime, so LCM(7, 10) = 7•10 = 70, and

⌊100/70⌋ ≈ ⌊1.42857⌋ = 1

(where ⌊<em>x</em>⌋ denotes the "floor" of <em>x</em>, meaning the largest integer that is smaller than <em>x</em>)

Then using the inclusion/exclusion principle, there are

10 + 14 - 1 = 23

numbers in the range 1-100 that are divisible by 10 or 7. In other words, add up the multiples of both 10 and 7, then subtract the common multiples, which are multiples of the LCM.

6 0

3 years ago

Determine the 10th term from the end of the AP 4, 9, 14​

Determine the 10th term from the end of the AP 4, 9, 14